The equation for the rate of product formation for simple enzyme reaction is given by (Where rmax, maximum reaction rate, Cs substrate concentration, Cp product concentration ES, CES enzyme-substrate concentration)
Options
A. rp = rmax Cs/(Km+Cs)
B. rp= rmax CES/(Km+ CES)
C. rp = rmax Cs/(Km+CES)
D. rp = rmax Cs/(Km+Cp)
Correct Answer
rp = rmax Cs/(Km+Cs)
Enzymes and Kinetics problems
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1. In the steady state the material balance equation for any component of a system is
Options
A. rate of addition + rate of removal - rate of formation = 0
B. rate of addition - rate of removal + rate of formation = 0
C. rate of addition + rate of removal + rate of formation = 0
8. An enzyme has a Km of 4.7 x 10-5M. If the Vmax of the preparation is 22m moles liter-1 min-1, what velocity would be observed in the presence of 2.0 x 10-4M substrate and 5.0 x 10-5M of a competitive inhibitor?