In Turbo C (DOS), determine the sizes printed by this program mixing dereferences in sizeof:\n\n#include<stdio.h>\n\nint main()\n{\n char huge *near *far *ptr1;\n char near *far *huge *ptr2;\n char far *huge *near *ptr3;\n printf("%d, %d, %d\n", sizeof(ptr1), sizeof(**ptr2), sizeof(ptr3));\n return 0;\n}

Introduction / Context:
sizeof can be applied either to a pointer variable or, after dereferencing, to another pointer type. This question mixes multi-level pointers with near/far/huge and asks you to resolve sizes under Turbo C (16-bit DOS).

Given Data / Assumptions:

• near = 2 bytes; far = 4 bytes; huge = 4 bytes.
• ptr1 is a far pointer; ptr2 is a huge pointer to a far pointer to a near char pointer; ptr3 is a near pointer.

Concept / Approach:
Unroll types stepwise. Each * removes one indirection level and exposes the next pointer's qualifier, which determines sizeof at that level.

Step-by-Step Solution:
1) sizeof(ptr1): ptr1 is far * ⇒ 4.2) sizeof(**ptr2): *ptr2 is a far *; **ptr2 is a near * ⇒ 2.3) sizeof(ptr3): ptr3 is near * ⇒ 2.4) Hence: 4, 2, 2.

Verification / Alternative check:
Print sizeof of each intermediate type in a separate test to see 4 (far *) and 2 (near *).

Why Other Options Are Wrong:
Option A: Treats all three as 4-byte pointers.
Option C/D: Introduce impossible 8-byte sizes or wrong bindings.

Common Pitfalls:
Assuming dereferencing always yields a char rather than a pointer type at the next level; here **ptr2 still yields a pointer (near *).

Final Answer:
4, 2, 2