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  • Question
  • What will be the output of the program in Turbo C?
    #include<stdio.h>
    
    int main(int argc, char *argv, char *env[])
    {
        int i;
        for(i=1; i<argc; i++)
            printf("%s\n", env[i]);
        return 0;
    }
    


  • Options
  • A. List of all environment variables
  • B. List of all command-line arguments
  • C. count of command-line arguments
  • D. Error: cannot have more than two arguments in main()

  • Correct Answer
  • List of all environment variables 


  • More questions

    • 1. Point out the error in the following program.
      #include<stdio.h>
      #include<stdarg.h>
      void varfun(int n, ...);
      
      int main()
      {
          varfun(3, 7, -11.2, 0.66);
          return 0;
      }
      void varfun(int n, ...)
      {
          float *ptr;
          int num;
          va_start(ptr, n);
          num = va_arg(ptr, int);
          printf("%d", num);
      }
      

    • Options
    • A. Error: too many parameters
    • B. Error: invalid access to list member
    • C. Error: ptr must be type of va_list
    • D. No error
    • Discuss
    • 2. Macros with arguments are allowed

    • Options
    • A. True
    • B. False
    • Discuss
    • 3. What will be the output of the program (in Turbo C)?
      #include<stdio.h>
      
      int fun(int *f)
      {
          *f = 10;
          return 0;
      }
      int main()
      {
          const int arr[5] = {1, 2, 3, 4, 5};
          printf("Before modification arr[3] = %d", arr[3]);
          fun(&arr[3]);
          printf("\nAfter modification arr[3] = %d", arr[3]);
          return 0;
      }
      

    • Options
    • A. Before modification arr[3] = 4
      After modification arr[3] = 10
    • B. Error: cannot convert parameter 1 from const int * to int *
    • C. Error: Invalid parameter
    • D. Before modification arr[3] = 4
      After modification arr[3] = 4
    • Discuss
    • 4. What will be the output of the program?
      #include<stdio.h>
      
      int main()
      {
          const int x=5;
          const int *ptrx;
          ptrx = &x;
          *ptrx = 10;
          printf("%d\n", x);
          return 0;
      }
      

    • Options
    • A. 5
    • B. 10
    • C. Error
    • D. Garbage value
    • Discuss
    • 5. What will be the output of the program?
      #include<stdio.h>
      int fun(int **ptr);
      
      int main()
      {
          int i=10;
          const int *ptr = &i;
          fun(&ptr);
          return 0;
      }
      int fun(int **ptr)
      {
          int j = 223;
          int *temp = &j;
          printf("Before changing ptr = %5x\n", *ptr);
          const *ptr = temp;
          printf("After changing ptr = %5x\n", *ptr);
          return 0;
      }
      

    • Options
    • A. Address of i
      Address of j
    • B. 10
      223
    • C. Error: cannot convert parameter 1 from 'const int **' to 'int **'
    • D. Garbage value
    • Discuss
    • 6. Point out the error in the program.
      #include<stdio.h>
      
      int main()
      {
          const int x;
          x=128;
          printf("%d\n", x);
          return 0;
      }
      

    • Options
    • A. Error: unknown data type const int
    • B. Error: const variable have been initialised when declared.
    • C. Error: stack overflow in x
    • D. No error
    • Discuss
    • 7. Point out the error in the program (in Turbo-C).
      #include<stdio.h>
      #define MAX 128
      
      int main()
      {
          const int max=128;
          char array[max];
          char string[MAX];
          array[0] = string[0] = 'A';
          printf("%c %c\n", array[0], string[0]);
          return 0;
      }
      

    • Options
    • A. Error: unknown max in declaration/Constant expression required
    • B. Error: invalid array string
    • C. None of above
    • D. No error. It prints A A
    • Discuss
    • 8. What will be the output of the program in TurboC?
      #include<stdio.h>
      int fun(int **ptr);
      
      int main()
      {
          int i=10, j=20;
          const int *ptr = &i;
          printf(" i = %5X", ptr);
          printf(" ptr = %d", *ptr);
          ptr = &j;
          printf(" j = %5X", ptr);
          printf(" ptr = %d", *ptr);
          return 0;
      }
      

    • Options
    • A. i= FFE2 ptr=12 j=FFE4 ptr=24
    • B. i= FFE4 ptr=10 j=FFE2 ptr=20
    • C. i= FFE0 ptr=20 j=FFE1 ptr=30
    • D. Garbage value
    • Discuss
    • 9. What will be the output of the program?
      #include<stdio.h>
      
      int main()
      {
          const int i=0;
          printf("%d\n", i++);
          return 0;
      }
      

    • Options
    • A. 10
    • B. 11
    • C. No output
    • D. Error: ++needs a value
    • Discuss
    • 10. Point out the error in the program.
      #include<stdio.h>
      #include<stdlib.h>
      
      union employee
      {
          char name[15];
          int age;
          float salary;
      };
      const union employee e1;
      
      int main()
      {
          strcpy(e1.name, "K");
          printf("%s", e1.name);    
          e1.age=85;
          printf("%d", e1.age);
          printf("%f", e1.salary);
          return 0;
      }
      

    • Options
    • A. Error: RValue required
    • B. Error: cannot modify const object
    • C. Error: LValue required in strcpy
    • D. No error
    • Discuss


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