In DOS/Turbo C style execution, argv[0] typically contains the full path of the running program. If the file myproc.c is in "C:\TC" and you run MYPROC.EXE from that directory, what does this program print? /* myproc.c */ #include<stdio.h> int main(int argc, char *argv[]) { printf("%s", argv[0]); return 0; }

Introduction / Context:
The problem reinforces that argv[0] is conventionally the program name or path with which the program was invoked. Under DOS/Turbo C, it often includes the full path and .EXE name when launched from the shell.

Given Data / Assumptions:

• Executable is MYPROC.EXE located in C:\\TC.
• Launched from that directory, so the shell provides the full path.
• Program prints argv[0] verbatim.

Concept / Approach:
argv[0] is populated by the host environment. Although not strictly standardized to be a full path, in this DOS/Turbo C context it typically is something like C:\\TC\\MYPROC.EXE when executed directly from that location.

Step-by-Step Solution:

Verification / Alternative check:
If you placed the EXE elsewhere or invoked via PATH without full path, argv[0] might differ, but the question specifies the DOS/Turbo C scenario yielding the full path.

Why Other Options Are Wrong:

• SAMPLE.C: That is a source file name, unrelated here.
• C:\\TC: That is a directory path, not the executable path.
• Error: There is no runtime error; printing a valid string is fine.
• myproc: Possible on some systems, but the question frames the full-path behavior.

Common Pitfalls:
Assuming argv[0] is always just the program name; environment conventions vary across systems and shells.

Final Answer:
C:\\TC\\MYPROC.EXE