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- Question
Point out the error in the program?
struct emp { int ecode; struct emp *e; };
Options- A. Error: in structure declaration
- B. Linker Error
- C. No Error
- D. None of above
- Correct Answer
- No Error
ExplanationThis type of declaration is called as self-referential structure. Here *e is pointer to a struct emp. - 1. Assuming, integer is 2 byte, What will be the output of the program?
#include
; int main() { printf("%x\n", -1>>1); return 0; }
Options- A. ffff
- B. 0fff
- C. 0000
- D. fff0 Discuss
- 2. What is the output of the program given below?
#include<stdio.h> int main() { enum status { pass, fail, atkt}; enum status stud1, stud2, stud3; stud1 = pass; stud2 = atkt; stud3 = fail; printf("%d, %d, %d\n", stud1, stud2, stud3); return 0; }
Options- A. 0, 1, 2
- B. 1, 2, 3
- C. 0, 2, 1
- D. 1, 3, 2 Discuss
- 3. What will be the output of the program?
#include<stdio.h> int main() { char ch; ch = 'A'; printf("The letter is"); printf("%c", ch >= 'A' && ch <= 'Z'? ch + 'a' - 'A':ch); printf("Now the letter is"); printf("%c\n", ch >= 'A' && ch <= 'Z'? ch : ch + 'a' - 'A'); return 0; }
Options- A. The letter is a
Now the letter is A - B. The letter is A
Now the letter is a - C. Error
- D. None of above Discuss
- 4. What will be the output of the program?
#include<stdio.h> int main() { int k, num=30; k = (num>5? (num <=10? 100 : 200): 500); printf("%d\n", num); return 0; }
Options- A. 200
- B. 30
- C. 100
- D. 500 Discuss
- 5. If a function contains two return statements successively, the compiler will generate warnings. Yes/No?
Options- A. Yes
- B. No Discuss
- 6. What will be the output of the program?
#include<stdio.h> int main() { char *str; str = "%s"; printf(str, "K\n"); return 0; }
Options- A. Error
- B. No output
- C. K
- D. %s Discuss
- 7. What will be the output of the program?
#include<stdio.h> int main() { char str1[] = "India"; char str2[] = "CURIOUSTAB"; char *s1 = str1, *s2=str2; while(*s1++ = *s2++) printf("%s", str1); printf("\n"); return 0; }
Options- A. CuriousTab
- B. BndiaBIdiaCURIOUSTABia
- C. India
- D. (null) Discuss
- 8. What will be the output of the program?
#include<stdio.h> int main() { int x=30, *y, *z; y=&x; /* Assume address of x is 500 and integer is 4 byte size */ z=y; *y++=*z++; x++; printf("x=%d, y=%d, z=%d\n", x, y, z); return 0; }
Options- A. x=31, y=502, z=502
- B. x=31, y=500, z=500
- C. x=31, y=498, z=498
- D. x=31, y=504, z=504 Discuss
- 9. What will be the output of the program?
#include<stdio.h> int main() { char *p; p="hello"; printf("%s\n", *&*&p); return 0; }
Options- A. llo
- B. hello
- C. ello
- D. h Discuss
- 10. What will be the output of the program?
#include<stdio.h> int main() { int i=3, *j, k; j = &i; printf("%d\n", i**j*i+*j); return 0; }
Options- A. 30
- B. 27
- C. 9
- D. 3 Discuss
More questions
Correct Answer: ffff
Explanation:
1's complement: Inverting the bits ( all 1s to 0s and all 0s to 1s)
2's complement: Adding 1 to the result of 1's complement.
Binary of 1(2byte) : 0000 0000 0000 0001 Representing -1: 1s complement of 1(2byte) : 1111 1111 1111 1110 Adding 1 to 1's comp. result : 1111 1111 1111 1111 Right shift 1bit(-1>>1): 1111 1111 1111 1111 (carry out 1) Hexadecimal : f f f f (Filled with 1s in the left side in the above step)Note:
1. Fill with 1s in the left side for right shift for negative numbers.
2. Fill with 0s in the right side for left shift for negative numbers.
3. Fill with 0s in the left side for right shift for positive numbers.
4. Fill with 0s in the right side for left shift for positive numbers.
Correct Answer: 0, 2, 1
Explanation:
stud1 = pass (value is 0)
stud2 = atkt (value is 2)
stud3 = fail (value is 1)
Hence it prints 0, 2, 1
Correct Answer: The letter is a
Now the letter is A
Explanation:
Step 2: printf("The letter is"); It prints "The letter is".
Step 3: printf("%c", ch >= 'A' && ch <= 'Z' ? ch + 'a' - 'A':ch);
The ASCII value of 'A' is 65 and 'a' is 97.
Here
=> ('A' >= 'A' && 'A' <= 'Z') ? (A + 'a' - 'A'):('A')
=> (TRUE && TRUE) ? (65 + 97 - 65) : ('A')
=> (TRUE) ? (97): ('A')
In printf the format specifier is '%c'. Hence prints 97 as 'a'.
Step 4: printf("Now the letter is"); It prints "Now the letter is".
Step 5: printf("%c\n", ch >= 'A' && ch <= 'Z' ? ch : ch + 'a' - 'A');
Here => ('A' >= 'A' && 'A' <= 'Z') ? ('A') : (A + 'a' - 'A')
=> (TRUE && TRUE) ? ('A') :(65 + 97 - 65)
=> (TRUE) ? ('A') : (97)
It prints 'A'
Hence the output is
The letter is a
Now the letter is A
Correct Answer: 30
Explanation:
Step 2: k = (num>5 ? (num <=10 ? 100 : 200): 500); This statement does not affect the output of the program. Because we are going to print the variable num in the next statement. So, we skip this statement.
Step 3: printf("%d\n", num); It prints the value of variable num '30'
Step 3: Hence the output of the program is '30'
Correct Answer: Yes
Explanation:
Example:
#include<stdio.h>
int mul(int, int); /* Function prototype */
int main()
{
int a = 4, b = 3, c;
c = mul(a, b);
printf("c = %d\n", c);
return 0;
}
int mul(int a, int b)
{
return (a * b);
return (a - b); /* Warning: Unreachable code */
}
Output:
c = 12
Correct Answer: K
Correct Answer: BndiaBIdiaCURIOUSTABia
Correct Answer: x=31, y=504, z=504
Correct Answer: hello
Correct Answer: 30
Comments
It is not sticky
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