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- Question
What will be the output of the program?
#include<stdio.h> int main() { int x=1, y=1; for(; y; printf("%d %d\n", x, y)) { y = x++ <= 5; } printf("\n"); return 0; }
Options- A. 2 1
3 1
4 1
5 1
6 1
7 0 - B. 2 1
3 1
4 1
5 1
6 1 - C. 2 1
3 1
4 1
5 1 - D. 2 2
3 3
4 4
5 5 - Correct Answer
- 2 1
3 1
4 1
5 1
6 1
7 0
- 1. What will be the output of the program?
#include<stdio.h> int main() { int i=3; switch(i) { case 1: printf("Hello\n"); case 2: printf("Hi\n"); case 3: continue; default: printf("Bye\n"); } return 0; }
Options- A. Error: Misplaced continue
- B. Bye
- C. No output
- D. Hello Hi Discuss
- 2. What will be the output of the program?
#include<stdio.h> int main() { char j=1; while(j < 5) { printf("%d, ", j); j = j+1; } printf("\n"); return 0; }
Options- A. 1 2 3 ... 127
- B. 1 2 3 ... 255
- C. 1 2 3 ... 127 128 0 1 2 3 ... infinite times
- D. 1, 2, 3, 4 Discuss
- 3. What will be the output of the program?
#include<stdio.h> int main() { char str[]="C-program"; int a = 5; printf(a >10?"Ps\n":"%s\n", str); return 0; }
Options- A. C-program
- B. Ps
- C. Error
- D. None of above Discuss
- 4. What will be the output of the program?
#include<stdio.h> int main() { int a = 300, b, c; if(a >= 400) b = 300; c = 200; printf("%d, %d, %d\n", a, b, c); return 0; }
Options- A. 300, 300, 200
- B. Garbage, 300, 200
- C. 300, Garbage, 200
- D. 300, 300, Garbage Discuss
- 5. What will be the output of the program?
#include<stdio.h> int main() { int a = 500, b = 100, c; if(!a >= 400) b = 300; c = 200; printf("b = %d c = %d\n", b, c); return 0; }
Options- A. b = 300 c = 200
- B. b = 100 c = garbage
- C. b = 300 c = garbage
- D. b = 100 c = 200 Discuss
- 6. Point out the error, if any in the for loop.
#include<stdio.h> int main() { int i=1; for(;;) { printf("%d\n", i++); if(i>10) break; } return 0; }
Options- A. There should be a condition in the for loop
- B. The two semicolons should be dropped
- C. The for loop should be replaced with while loop.
- D. No error Discuss
- 7. Point out the error, if any in the program.
#include<stdio.h> int main() { int P = 10; switch(P) { case 10: printf("Case 1"); case 20: printf("Case 2"); break; case P: printf("Case 2"); break; } return 0; }
Options- A. Error: No default value is specified
- B. Error: Constant expression required at line case P:
- C. Error: There is no break statement in each case.
- D. No error will be reported. Discuss
- 8. Point out the error, if any in the while loop.
#include<stdio.h> int main() { int i=1; while() { printf("%d\n", i++); if(i>10) break; } return 0; }
Options- A. There should be a condition in the while loop
- B. There should be at least a semicolon in the while
- C. The while loop should be replaced with for loop.
- D. No error Discuss
- 9. Point out the error, if any in the program.
#include<stdio.h> int main() { int i = 1; switch(i) { printf("This is c program."); case 1: printf("Case1"); break; case 2: printf("Case2"); break; } return 0; }
Options- A. Error: No default specified
- B. Error: Invalid printf statement after switch statement
- C. No Error and prints "Case1"
- D. None of above Discuss
- 10. Point out the error, if any in the while loop.
#include<stdio.h> int main() { void fun(); int i = 1; while(i <= 5) { printf("%d\n", i); if(i>2) goto here; } return 0; } void fun() { here: printf("It works"); }
Options- A. No Error: prints "It works"
- B. Error: fun() cannot be accessed
- C. Error: goto cannot takeover control to other function
- D. No error Discuss
Control Instructions problems
Search Results
Correct Answer: Error: Misplaced continue
Explanation:
The keyword continue cannot be used in switch case. It must be used in for or while or do while loop. If there is any looping statement in switch case then we can use continue.
Correct Answer: 1, 2, 3, 4
Correct Answer: C-program
Explanation:
Step 1: char str[]="C-program"; here variable str contains "C-program".
Step 2: int a = 5; here variable a contains "5".
Step 3: printf(a >10?"Ps\n":"%s\n", str); this statement can be written as
Step 2: int a = 5; here variable a contains "5".
Step 3: printf(a >10?"Ps\n":"%s\n", str); this statement can be written as
if(a > 10)
{
printf("Ps\n");
}
else
{
printf("%s\n", str);
}
Here we are checking a > 10 means 5 > 10. Hence this condition will be failed. So it prints variable str.
Hence the output is "C-program".
Correct Answer: 300, Garbage, 200
Explanation:
Step 1: int a = 300, b, c; here variable a is initialized to '300', variable b and c are declared, but not initialized.
Step 2: if(a >= 400) means if(300 >= 400). Hence this condition will be failed.
Step 3: c = 200; here variable c is initialized to '200'.
Step 4: printf("%d, %d, %d\n", a, b, c); It prints "300, garbage value, 200". because variable b is not initialized.
Step 2: if(a >= 400) means if(300 >= 400). Hence this condition will be failed.
Step 3: c = 200; here variable c is initialized to '200'.
Step 4: printf("%d, %d, %d\n", a, b, c); It prints "300, garbage value, 200". because variable b is not initialized.
Correct Answer: b = 100 c = 200
Explanation:
Initially variables a = 500, b = 100 and c is not assigned.
Step 1: if(!a >= 400)
Step 2: if(!500 >= 400)
Step 3: if(0 >= 400)
Step 4: if(FALSE) Hence the if condition is failed.
Step 5: So, variable c is assigned to a value '200'.
Step 6: printf("b = %d c = %d\n", b, c); It prints value of b and c.
Hence the output is "b = 100 c = 200"
Correct Answer: No error
Explanation:
Step 1: for(;;) this statement will genereate infinite loop.
Step 2: printf("%d\n", i++); this statement will print the value of variable i and increement i by 1(one).
Step 3: if(i>10) here, if the variable i value is greater than 10, then the for loop breaks.
Step 2: printf("%d\n", i++); this statement will print the value of variable i and increement i by 1(one).
Step 3: if(i>10) here, if the variable i value is greater than 10, then the for loop breaks.
Hence the output of the program is
1
2
3
4
5
6
7
8
9
10
Correct Answer: Error: Constant expression required at line case P:
Explanation:
The compiler will report the error "Constant expression required" in the line case P: . Because, variable names cannot be used with case statements.
The case statements will accept only constant expression.
Correct Answer: There should be a condition in the while loop
Explanation:
The while() loop must have conditional expression or it shows "Expression syntax" error.
Example: while(i > 10){ ... }
Correct Answer: No Error and prints "Case1"
Explanation:
switch(i) becomes switch(1), then the case 1: block is get executed. Hence it prints "Case1".
printf("This is c program."); is ignored by the compiler.
Hence there is no error and prints "Case1".
Correct Answer: Error: goto cannot takeover control to other function
Explanation:
A label is used as the target of a goto statement, and that label must be within the same function as the goto statement.
Syntax: goto <identifier> ;
Control is unconditionally transferred to the location of a local label specified by <identifier>.
Example:
#include <stdio.h>
int main()
{
int i=1;
while(i>0)
{
printf("%d", i++);
if(i==5)
goto mylabel;
}
mylabel:
return 0;
}
Output: 1,2,3,4
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