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- Question
Can the fixed arguments passed to the function that accepts variable argument list, occur at the end?
Options- A. Yes
- B. No
- Correct Answer
- No
- 1. Can we write a function that takes a variable argument list and passes the list to another function?
Options- A. Yes
- B. No Discuss
- 2. While defining a variable argument list function we drop the ellipsis(...)?
Options- A. Yes
- B. No Discuss
- 3. Can we pass a variable argument list to a function at run-time?
Options- A. Yes
- B. No Discuss
- 4. It is necessary to call the macro va_end if va_start is called in the function.
Options- A. Yes
- B. No Discuss
- 5. In a function that receives variable number of arguments the fixed arguments passed to the function can be at the end of argument list.
Options- A. True
- B. False Discuss
- 6. Is it necessary that in a function which accepts variable argument list there should be at least be one fixed argument?
Options- A. Yes
- B. No Discuss
- 7. The macro va_arg is used to extract an argument from the fixed micro argument list and advance the pointer to the next argument.
Options- A. Yes
- B. No Discuss
- 8. What will be the output of the program?
#include<stdio.h> #include<string.h> int main() { char dest[] = {97, 97, 0}; char src[] = "aaa"; int i; if((i = memcmp(dest, src, 2))==0) printf("Got it"); else printf("Missed"); return 0; }
Options- A. Missed
- B. Got it
- C. Error in memcmp statement
- D. None of above Discuss
- 9. What will be the output of the program?
#include<stdio.h> int main() { int i; i = scanf("%d %d", &i, &i); printf("%d\n", i); return 0; }
Options- A. 1
- B. 2
- C. Garbage value
- D. Error: cannot assign scanf to variable Discuss
- 10. What will be the output of the program?
#include<stdio.h> #include<math.h> int main() { float i = 2.5; printf("%f, %d", floor(i), ceil(i)); return 0; }
Options- A. 2, 3
- B. 2.000000, 3
- C. 2.000000, 0
- D. 2, 0 Discuss
Variable Number of Arguments problems
Search Results
Correct Answer: Yes
Correct Answer: Yes
Correct Answer: No
Explanation:
Every actual argument list must be known at compile time. In that sense it is not truly a variable argument list.
Correct Answer: Yes
Correct Answer: False
Correct Answer: Yes
Correct Answer: No
Correct Answer: Got it
Explanation:
memcmp compares the first 2 bytes of the blocks dest and src as unsigned chars. So, the ASCII value of 97 is 'a'.
if((i = memcmp(dest, src, 2))==0) When comparing the array dest and src as unsigned chars, the first 2 bytes are same in both variables.so memcmp returns '0'.
Then, the if(0=0) condition is satisfied. Hence the output is "Got it".
Correct Answer: 2
Explanation:
scanf() returns the number of variables to which you are provding the input.
i = scanf("%d %d", &i, &i); Here Scanf() returns 2. So i = 2.
printf("%d\n", i); Here it prints 2.
Correct Answer: 2.000000, 0
Explanation:
Both ceil() and floor() return the integer found as a double.
floor(2.5) returns the largest integral value(round down) that is not greater than 2.5. So output is 2.000000.
ceil(2.5) returns 3, while converting the double to int it returns '0'.
So, the output is '2.000000, 0'.
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