If an unsigned int is 2 bytes wide then, What will be the output of the program?

#include<stdio.h>

int main()
{
    unsigned int m = 32;
    printf("%x\n", ~m);
    return 0;
}

#include<stdio.h>

int main()
{
    unsigned int a=0xffff;
    ~a;
    printf("%x\n", a);
    return 0;
}

#include<stdio.h>

int main()
{
    int i=32, j=0x20, k, l, m;
    k=i|j;
    l=i&j;
    m=k^l;
    printf("%d, %d, %d, %d, %d\n", i, j, k, l, m);
    return 0;
}

#include<stdio.h>

int main()
{
    int i=4, j=8;
    printf("%d, %d, %d\n", i|j&j|i, i|j&&j|i, i^j);
    return 0;
}

#include<stdio.h>

int main()
{
    char c=48;
    int i, mask=01;
    for(i=1; i<=5; i++)
    {
        printf("%c", c|mask);
        mask = mask<<1;
    }
    return 0;
}

#include<stdio.h>

int main()
{
    unsigned int res;
    res = (64 >>(2+1-2)) & (~(1<<2));
    printf("%d\n", res);
    return 0;
}

#include<stdio.h>

int main()
{
    printf("%d >> %d %d >> %d\n", 4 >> 1, 8 >> 1);
    return 0;
}

#define P printf("%d\n", -1^~0);
#define M(P) int main()\
             {\
                P\
                return 0;\
             }
M(P)

#include<stdio.h>

int main()
{
    printf("%d %d\n", 32<<1, 32<<0);
    printf("%d %d\n", 32<<-1, 32<<-0);
    printf("%d %d\n", 32>>1, 32>>0);
    printf("%d %d\n", 32>>-1, 32>>-0);
    return 0;
}

#include<stdio.h>

int main()
{
    printf("%x\n", -1<<3);
    return 0;
}

#include<stdio.h>

int main()
{
    unsigned char i = 0x80;
    printf("%d\n", i<<1);
    return 0;
}