#include<stdio.h> int main() { unsigned int res; res = (64 >>(2+1-2)) & (~(1<<2)); printf("%d\n", res); return 0; }
#include<stdio.h> int check(int); int main() { int i=45, c; c = check(i); printf("%d\n", c); return 0; } int check(int ch) { if(ch >= 45) return 100; else return 10; }
Step 2: int l=45, c; The variable i and c are declared as an integer type and i is initialized to 45.
The function check(i) return 100 if the given value of variable i is >=(greater than or equal to) 45, else it will return 10.
Step 3: c = check(i); becomes c = check(45); The function check() return 100 and it get stored in the variable c.(c = 100)
Step 4: printf("%d\n", c); It prints the value of variable c.
Hence the output of the program is '100'.
#include<stdio.h> int main() { int i=1; for(;;) { printf("%d\n", i++); if(i>10) break; } return 0; }
Hence the output of the program is
1
2
3
4
5
6
7
8
9
10
#include<stdio.h> int main() { float a=0.7; if(a < 0.7) printf("C\n"); else printf("C++\n"); return 0; }
#include<stdio.h>
int main()
{
float a=0.7;
printf("%.10f %.10f\n",0.7, a);
return 0;
}
Output:
0.7000000000 0.6999999881
#include<stdio.h> int main() { printf("%x\n", -2<<2); return 0; }
#include<stdio.h> int main() { int i; i = printf("How r u\n"); i = printf("%d\n", i); printf("%d\n", i); return 0; }
i = printf("%d\n", i); In the previous step the value of i is 8. So it prints "8" with a new line character and returns the length of string printed then assign it to variable i. So i = 2 (length of '\n' is 1).
printf("%d\n", i); In the previous step the value of i is 2. So it prints "2".
#include<stdio.h> int main() { #ifdef NOTE int a; a=10; #else int a; a=20; #endif printf("%d\n", a); return 0; }
The macro #ifdef NOTE evaluates the given expression to 1. If satisfied it executes the #ifdef block statements. Here #ifdef condition fails because the Macro NOTE is nowhere declared.
Hence the #else block gets executed, the variable a is declared and assigned a value of 20.
printf("%d\n", a); It prints the value of variable a 20.
#ifndef XSTRING_H
#define XSTRING_H defines the same preprocessor symbol,
Finally, the last line of the file, #endif
#include<stdio.h> #define INFINITELOOP while(1) int main() { INFINITELOOP printf("CuriousTab"); return 0; }
The macro INFINITELOOP while(1) replaces the text 'INFINITELOOP' by 'while(1)'
In the main function, while(1) satisfies the while condition and it prints "CuriousTab". Then it comes to while(1) and the loop runs infinitely.
void *(ptr)*int;
void *(*ptr)()
void *(*ptr)(*)
void (*ptr)()
void (*ptr)()
#include<stdio.h> #define MIN(x, y) (x<y)? x : y; int main() { int x=3, y=4, z; z = MIN(x+y/2, y-1); if(z > 0) printf("%d\n", z); return 0; }
Step 1: int x=3, y=4, z; The variable x, y, z are declared as an integer type and the variable x, y are initialized to value 3, 4 respectively.
Step 2: z = MIN(x+y/2, y-1); becomes,
=> z = (x+y/2 < y-1)? x+y/2 : y - 1;
=> z = (3+4/2 < 4-1)? 3+4/2 : 4 - 1;
=> z = (3+2 < 4-1)? 3+2 : 4 - 1;
=> z = (5 < 3)? 5 : 3;
The macro return the number 3 and it is stored in the variable z.
Step 3: if(z > 0) becomes if(3 > 0) here the if condition is satisfied. It executes the if block statements.
Step 4: printf("%d\n", z);. It prints the value of variable z.
Hence the output of the program is 3
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