What will be the output of the program?

#include<stdio.h>
char *str = "char *str = %c%s%c; main(){ printf(str, 34, str, 34);}";

int main()
{
    printf(str, 34, str, 34);
    return 0;
}

#include<stdio.h>

int main()
{
    FILE *fs, *ft;
    char c[10];
    fs = fopen("source.txt", "r");
    c[0] = getc(fs);
    fseek(fs, 0, SEEK_END);
    fseek(fs, -3L, SEEK_CUR);
    fgets(c, 5, fs);
    puts(c);
    return 0;
}

#include<stdio.h>

int main()
{
    char *p;
    p="%d\n";
    p++;
    p++;
    printf(p-2, 23);
    return 0;
}

#include<stdio.h>

int main()
{
    printf("%c\n", ~('C'*-1));
    return 0;
}

#include<stdio.h>

int main()
{
    FILE *fp;
    unsigned char ch;
     /* file 'abc.c' contains "This is CuriousTab " */
    fp=fopen("abc.c", "r");
    if(fp == NULL)
    {
        printf("Unable to open file");
        exit(1);
    }
    while((ch=getc(fp)) != EOF)
        printf("%c", ch);

    fclose(fp);
    printf("\n", ch);
    return 0;
}

#include<stdio.h>

int main()
{
    int i;
    printf("%d\n", scanf("%d", &i));
    return 0;
}

#include<stdio.h>

int main()
{
    printf("%%%%\n");
    return 0;
}

#include;

int main()
{
    printf("%x\n", -1>>1);
    return 0;
}

#include<stdio.h>

int main()
{
    unsigned int res;
    res = (64 >>(2+1-2)) & (~(1<<2));
    printf("%d\n", res);
    return 0;
}

#include<stdio.h>

int main()
{
    char c=48;
    int i, mask=01;
    for(i=1; i<=5; i++)
    {
        printf("%c", c|mask);
        mask = mask<<1;
    }
    return 0;
}

#include<stdio.h>

int main()
{
    int i=4, j=8;
    printf("%d, %d, %d\n", i|j&j|i, i|j&&j|i, i^j);
    return 0;
}