#include<stdio.h> int main() { printf("%d, %d, %d", sizeof(3.0f), sizeof('3'), sizeof(3.0)); return 0; }
printf("%d, %d, %d", sizeof(3.0f), sizeof('3'), sizeof(3.0));
The sizeof function returns the size of the given expression.
sizeof(3.0f) is a floating point constant. The size of float is 4 bytes
sizeof('3') It converts '3' in to ASCII value.. The size of int is 2 bytes
sizeof(3.0) is a double constant. The size of double is 8 bytes
Hence the output of the program is 4,2,8
Note: The above program may produce different output in other platform due to the platform dependency of C compiler.
In Turbo C, 4 2 8. But in GCC, the output will be 4 4 8.
#include<stdio.h> int main() { static char mess[6][30] = {"Don't walk in front of me...", "I may not follow;", "Don't walk behind me...", "Just walk beside me...", "And be my friend." }; printf("%c, %c\n", *(mess[2]+9), *(*(mess+2)+9)); return 0; }
#include<stdio.h> void swap(char *, char *); int main() { char *pstr[2] = {"Hello", "CuriousTab"}; swap(pstr[0], pstr[1]); printf("%s\n%s", pstr[0], pstr[1]); return 0; } void swap(char *t1, char *t2) { char *t; t=t1; t1=t2; t2=t; }
Step 2: char *pstr[2] = {"Hello", "CuriousTab"}; The variable pstr is declared as an pointer to the array of strings. It is initialized to
pstr[0] = "Hello", pstr[1] = "CuriousTab"
Step 3: swap(pstr[0], pstr[1]); The swap function is called by "call by value". Hence it does not affect the output of the program.
If the swap function is "called by reference" it will affect the variable pstr.
Step 4: printf("%s\n%s", pstr[0], pstr[1]); It prints the value of pstr[0] and pstr[1].
Hence the output of the program is
Hello
CuriousTab
#include<stdio.h> int main() { char str[10] = "India"; str[6] = "CURIOUSTAB"; printf("%s\n", str); return 0; }
#include<stdio.h> #include<string.h> int main() { printf("%d\n", strlen("123456")); return 0; }
Therefore, strlen("123456") returns 6.
Hence the output of the program is "6".
#include<stdio.h> int main() { int i; char a[] = "\0"; if(printf("%s", a)) printf("The string is empty\n"); else printf("The string is not empty\n"); return 0; }
Step 1: char a[] = "\0"; The variable a is declared as an array of characters and it initialized with "\0". It denotes that the string is empty.
Step 2: if(printf("%s", a)) The printf() statement does not print anything, so it returns '0'(zero). Hence the if condition is failed.
In the else part it prints "The string is not empty".
#include<stdio.h> int main() { char a[] = "Visual C++"; char *b = "Visual C++"; printf("%d, %d\n", sizeof(a), sizeof(b)); printf("%d, %d", sizeof(*a), sizeof(*b)); return 0; }
#include<stdio.h> int main() { char str[7] = "CuriousTab"; printf("%s\n", str); return 0; }
#include<stdio.h> int main() { FILE *fp1, *fp2; fp1=fopen("file.c", "w"); fp2=fopen("file.c", "w"); fputc('A', fp1); fputc('B', fp2); fclose(fp1); fclose(fp2); return 0; }
Hence the file1.c contents is 'B'.
#include<stdio.h> int main() { int k=1; printf("%d == 1 is" "%s\n", k, k==1?"TRUE":"FALSE"); return 0; }
Step 2: printf("%d == 1 is" "%s\n", k, k==1?"TRUE":"FALSE"); becomes
=> k==1?"TRUE":"FALSE"
=> 1==1?"TRUE":"FALSE"
=> "TRUE"
Therefore the output of the program is 1 == 1 is TRUE
#include<stdio.h> int main() { FILE *ptr; char i; ptr = fopen("myfile.c", "r"); while((i=fgetc(ptr))!=NULL) printf("%c", i); return 0; }
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.