What will be the output of the program? #include int main() { char str[7] = "CuriousTab"; printf("%s ", str); return 0; }

Question

What will be the output of the program? #include<stdio.h>  int main() {     char str[7] = "CuriousTab";     printf("%s
", str);     return 0; }

Accepted Answer

Here str[] has declared as 7 character array and into a 8 character is stored. This will result in overwriting of the byte beyond 7 byte reserved for '\0'.

What will be the output of the program? #include<stdio.h> int main() { char str[7] = "CuriousTab"; printf("%s\n", str); return 0; }

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