Discussion
Home ‣ C Programming ‣ Strings Comments
- Question
What will be the output of the program?
#include<stdio.h> int main() { char *names[] = { "Suresh", "Siva", "Sona", "Baiju", "Ritu"}; int i; char *t; t = names[3]; names[3] = names[4]; names[4] = t; for(i=0; i<=4; i++) printf("%s,", names[i]); return 0; }
Options- A. Suresh, Siva, Sona, Baiju, Ritu
- B. Suresh, Siva, Sona, Ritu, Baiju
- C. Suresh, Siva, Baiju, Sona, Ritu
- D. Suresh, Siva, Ritu, Sona, Baiju
- Correct Answer
- Suresh, Siva, Sona, Ritu, Baiju
ExplanationStep 1: char *names[] = { "Suresh", "Siva", "Sona", "Baiju", "Ritu"}; The variable names is declared as an pointer to a array of strings.Step 2: int i; The variable i is declared as an integer type.
Step 3: char *t; The variable t is declared as pointer to a string.
Step 4: t = names[3]; names[3] = names[4]; names[4] = t; These statements the swaps the 4 and 5 element of the array names.
Step 5: for(i=0; i<=4; i++) printf("%s,", names[i]); These statement prints the all the value of the array names.
Hence the output of the program is "Suresh, Siva, Sona, Ritu, Baiju".
Strings problems
Search Results
- 1. What will be the output of the program?
#include<stdio.h> int main() { printf("India", "CURIOUSTAB\n"); return 0; }
Options- A. Error
- B. India CURIOUSTAB
- C. India
- D. CURIOUSTAB Discuss
Correct Answer: India
Explanation:
printf("India", "CURIOUSTAB\n"); It prints "India". Because ,(comma) operator has Left to Right associativity. After printing "India", the statement got terminated.- 2. What will be the output of the program?
#include<stdio.h> #include<string.h> int main() { char str1[5], str2[5]; int i; gets(str1); gets(str2); i = strcmp(str1, str2); printf("%d\n", i); return 0; }
Options- A. Unpredictable integer value
- B. 0
- C. -1
- D. Error Discuss
Correct Answer: Unpredictable integer value
Explanation:
gets() gets collects a string of characters terminated by a new line from the standard input stream stdin.The gets(str1) read the input string from user and store in variable str1.
The gets(str2) read the input string from user and store in variable str2.
The code i = strcmp(str1, str2); The strcmp not only returns -1, 0 and +1, but also other negative or positive values. So the value of i is "unpredictable integer value".
printf("%d\n", i); It prints the value of variable i.
- 3. What will be the output of the program?
#include<stdio.h> #include<string.h> int main() { char str[] = "India\0\CURIOUSTAB\0"; printf("%s\n", str); return 0; }
Options- A. CURIOUSTAB
- B. India
- C. India CURIOUSTAB
- D. India\0CURIOUSTAB Discuss
Correct Answer: India
Explanation:
A string is a collection of characters terminated by '\0'.Step 1: char str[] = "India\0\CURIOUSTAB\0"; The variable str is declared as an array of characters and initialized with value "India"
Step 2: printf("%s\n", str); It prints the value of the str.
The output of the program is "India".
- 4. What will be the output of the program?
#include<stdio.h> #include<string.h> int main() { char str[] = "India\0\CURIOUSTAB\0"; printf("%d\n", strlen(str)); return 0; }
Options- A. 10
- B. 6
- C. 5
- D. 11 Discuss
Correct Answer: 5
Explanation:
The function strlen returns the number of characters int the given string.Therefore, strlen(str) becomes strlen("India") contains 5 characters. A string is a collection of characters terminated by '\0'.
The output of the program is "5".
- 5. What will be the output of the program?
#include<stdio.h> int main() { char str1[] = "Hello"; char str2[] = "Hello"; if(str1 == str2) printf("Equal\n"); else printf("Unequal\n"); return 0; }
Options- A. Equal
- B. Unequal
- C. Error
- D. None of above Discuss
Correct Answer: Unequal
Explanation:
Step 1: char str1[] = "Hello"; The variable str1 is declared as an array of characters and initialized with a string "Hello".Step 2: char str2[] = "Hello"; The variable str2 is declared as an array of characters and initialized with a string "Hello".
We have use strcmp(s1,s2) function to compare strings.
Step 3: if(str1 == str2) here the address of str1 and str2 are compared. The address of both variable is not same. Hence the if condition is failed.
Step 4: At the else part it prints "Unequal".
- 6. What will be the output of the program?
#include<stdio.h> int main() { static char s[25] = "The cocaine man"; int i=0; char ch; ch = s[++i]; printf("%c", ch); ch = s[i++]; printf("%c", ch); ch = i++[s]; printf("%c", ch); ch = ++i[s]; printf("%c", ch); return 0; }
Options- A. hhe!
- B. he c
- C. The c
- D. Hhec Discuss
Correct Answer: hhe!
- 7. What will be the output of the program If characters 'a', 'b' and 'c' enter are supplied as input?
#include<stdio.h> int main() { void fun(); fun(); printf("\n"); return 0; } void fun() { char c; if((c = getchar())!= '\n') fun(); printf("%c", c); }
Options- A. abc abc
- B. bca
- C. Infinite loop
- D. cba Discuss
Correct Answer: cba
Explanation:
Step 1: void fun(); This is the prototype for the function fun().Step 2: fun(); The function fun() is called here.
The function fun() gets a character input and the input is terminated by an enter key(New line character). It prints the given character in the reverse order.
The given input characters are "abc"
Output: cba
- 8. What will be the output of the program?
#include<stdio.h> #include<string.h> int main() { char sentence[80]; int i; printf("Enter a line of text\n"); gets(sentence); for(i=strlen(sentence)-1; i >=0; i--) putchar(sentence[i]); return 0; }
Options- A. The sentence will get printed in same order as it entered
- B. The sentence will get printed in reverse order
- C. Half of the sentence will get printed
- D. None of above Discuss
Correct Answer: The sentence will get printed in reverse order
- 9. What will be the output of the program?
#include<stdio.h> #include<string.h> int main() { printf("%c\n", "abcdefgh"[4]); return 0; }
Options- A. Error
- B. d
- C. e
- D. abcdefgh Discuss
Correct Answer: e
Explanation:
printf("%c\n", "abcdefgh"[4]); It prints the 5 character of the string "abcdefgh".Hence the output is 'e'.
- 10. What will be the output of the program?
#include<stdio.h> int main() { char str[25] = "CuriousTab"; printf("%s\n", &str+2); return 0; }
Options- A. Garbage value
- B. Error
- C. No output
- D. diaCURIOUSTAB Discuss
Correct Answer: Garbage value
Explanation:
Step 1: char str[25] = "CuriousTab"; The variable str is declared as an array of characteres and initialized with a string "CuriousTab".Step 2: printf("%s\n", &str+2);
=> In the printf statement %s is string format specifier tells the compiler to print the string in the memory of &str+2
=> &str is a location of string "CuriousTab". Therefore &str+2 is another memory location.
Hence it prints the Garbage value.
Comments
There are no comments.
More in C Programming:
Programming
Copyright ©CuriousTab. All rights reserved.
- 1. What will be the output of the program?