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- Question
Is it true that too many recursive calls may result into stack overflow?
Options- A. Yes
- B. No
- Correct Answer
- Yes
ExplanationYes, too many recursive calls may result into stack overflow. because when a function is called its return address is stored in stack.After sometime the stack memory will be filled completely. Hence stack overflow error will occur.
More questions
- 1. Which of the following is the correct order if calling functions in the below code?
a = f1(23, 14) * f2(12/4) + f3();
Options- A. f1, f2, f3
- B. f3, f2, f1
- C. Order may vary from compiler to compiler
- D. None of above Discuss
Correct Answer: Order may vary from compiler to compiler
Explanation:
Here, Multiplication will happen before the addition, but in which order the functions would be called is undefined. In an arithmetic expression the parenthesis tell the compiler which operands go with which operators but do not force the compiler to evaluate everything within the parenthesis first.- 2. If a variable is a pointer to a structure, then which of the following operator is used to access data members of the structure through the pointer variable?
Options- A. .
- B. &
- C. *
- D. -> Discuss
Correct Answer: ->
- 3. Assuming a integer 2-bytes, What will be the output of the program?
#include<stdio.h> int main() { printf("%x\n", -1<<3); return 0; }
Options- A. ffff
- B. fff8
- C. 0
- D. -1 Discuss
Correct Answer: fff8
Explanation:
The system will treat negative numbers in 2's complement method.
Example:
Assume the size of int is 2-bytes(16 bits). The integer value 1 is represented as given below:
Binary of 1: 00000000 00000001 (this is for positive value of 1)
1's complement of binary 1: 11111111 11111110
2's complement of binary 1: 11111111 11111111
Thy system will store '11111111 11111111' in memory to represent '-1'.
If we do left shift (3 bits) on 11111111 11111111 it will become as given below:
11111111 11111111 ---(left shift 3 times)---> 11111111 11111000.
So, 11111111 11111000 ---(binary to hex)---> FF F8. (Required Answer)
Note:
How is the negative number obtained from 2's complement value?
As stated above, -1 is represented as '11111111 11111111' in memory.
So, the system will take 2's complement of '11111111 11111111' to the get the original negative value back.
Example:
Bit Representation of -1: 11111111 11111111
Since the left most bit is 1, it is a negative number. Then the value is
1's complement: 00000000 00000000
2's complement: 00000000 00000001 (Add 1 to the above result)
Therefore, '00000000 00000001' = 1 and the sign is negative.
Hence the value is -1.- 4. A float is 4 bytes wide, whereas a double is 8 bytes wide.
Options- A. True
- B. False Discuss
Correct Answer: True
Explanation:
True,
float = 4 bytes.
double = 8 bytes.- 5. What will be the output of the program?
#include<stdio.h> #include<string.h> int main() { printf("%c\n", "abcdefgh"[4]); return 0; }
Options- A. Error
- B. d
- C. e
- D. abcdefgh Discuss
Correct Answer: e
Explanation:
printf("%c\n", "abcdefgh"[4]); It prints the 5 character of the string "abcdefgh".Hence the output is 'e'.
- 6. What is the output of the program?
#include<stdio.h> int main() { union a { int i; char ch[2]; }; union a u; u.ch[0] = 3; u.ch[1] = 2; printf("%d, %d, %d\n", u.ch[0], u.ch[1], u.i); return 0; }
Options- A. 3, 2, 515
- B. 515, 2, 3
- C. 3, 2, 5
- D. None of these Discuss
Correct Answer: 3, 2, 515
Explanation:
printf("%d, %d, %d\n", u.ch[0], u.ch[1], u.i); It prints the value of u.ch[0] = 3, u.ch[1] = 2 and it prints the value of u.i means the value of entire union size.
So the output is 3, 2, 515.
- 7. What will be the output of the program?
#include<stdio.h> int main() { int X=40; { int X=20; printf("%d ", X); } printf("%d\n", X); return 0; }
Options- A. 40 40
- B. 20 40
- C. 20
- D. Error Discuss
Correct Answer: 20 40
Explanation:
In case of a conflict between a local variable and global variable, the local variable gets priority.- 8. What will be the output of the program?
#include<stdio.h> int main() { char c=48; int i, mask=01; for(i=1; i<=5; i++) { printf("%c", c|mask); mask = mask<<1; } return 0; }
Options- A. 12400
- B. 12480
- C. 12500
- D. 12556 Discuss
Correct Answer: 12480
- 9. What will be the output of the program?
#include<stdio.h> int main() { char str = "CuriousTab"; printf("%s\n", str); return 0; }
Options- A. Error
- B. CuriousTab
- C. Base address of str
- D. No output Discuss
Correct Answer: Error
Explanation:
The line char str = "CuriousTab"; generates "Non portable pointer conversion" error.To eliminate the error, we have to change the above line to
char *str = "CuriousTab"; (or) char str[] = "CuriousTab";
Then it prints "CuriousTab".
- 10. What will be the output of the program?
#include<stdio.h> int main() { static char s[25] = "The cocaine man"; int i=0; char ch; ch = s[++i]; printf("%c", ch); ch = s[i++]; printf("%c", ch); ch = i++[s]; printf("%c", ch); ch = ++i[s]; printf("%c", ch); return 0; }
Options- A. hhe!
- B. he c
- C. The c
- D. Hhec Discuss
Correct Answer: hhe!
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- 1. Which of the following is the correct order if calling functions in the below code?
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