Difficulty: Easy
Correct Answer: n-type
Explanation:
Introduction / Context:
Doping controls carrier type and concentration in semiconductors. Pentavalent dopants in group-IV semiconductors provide extra electrons near the conduction band and are central to forming n-type regions in diodes and transistors.
Given Data / Assumptions:
Concept / Approach:
Pentavalent atoms substitute for a host atom and form four covalent bonds, leaving one loosely bound electron. This donor electron is thermally ionized at room temperature, contributing a free electron to the conduction band and creating a positively charged donor ion. Thus electrons become majority carriers and the material is n-type.
Step-by-Step Solution:
Identify dopant valence: 5 → donor.Ionization releases an electron to the conduction band.Carrier balance shifts: n ≫ p → n-type behavior.
Verification / Alternative check:
Energy band diagrams show donor levels slightly below the conduction band; at room temperature most donors are ionized, raising electron concentration.
Why Other Options Are Wrong:
p-type requires acceptors (trivalent B, Al, Ga). “Intrinsic” ignores the dopant. “Neutral with no change” is false; carrier concentration changes markedly. “Degenerate p-type” is unrelated to donor doping.
Common Pitfalls:
Final Answer:
n-type
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