Discussion
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- Question
Correction per chain length of 100 links along a slope of ?° is
Options- A.
- B.
- C.
- D. 1.5?3.
- Correct Answer
-
- 1. If i is the stadia distance, f is the focal length and d is the distance between the objective and vertical axis of the techeometer, the multiplying constant, is
Options- A. f/i
- B. i/f
- C. (f + d)
- D. f/d. Discuss
- 2. If 50 m point of a 100 m tape is 50 cm off line, and 50 m sections are straight, an error is generated equal to
Options- A.
- B.
- C.
- D.
.
Discuss
- 3. The angle of intersection of a curve is the angle between
Options- A. back tangent and forward tangent
- B. prolongation of back tangent and forward tangent
- C. forward tangent and long chord
- D. back tangent and long chord. Discuss
- 4. While setting a plane table at a station it was found that the error in centering was 30 cm away from the ray of length 40 m drawn from the station. If the scale of the plan is 1 cm = 2 cm, the displacement of the end of the ray in plan from the true position will be
Options- A. 0.02 cm
- B. 0.15 cm
- C. 02 cm
- D. 0.1 cm Discuss
- 5. For taking offsets with an optical square on the right hand side of the chain line, it is held
Options- A. by right hand upside down
- B. by left hand upright
- C. by right hand upright
- D. by left hand up side down. Discuss
- 6. Location of contour gradient for a high way is best set out from
Options- A. ridge down the hill
- B. saddle down the hill
- C. bottom to the ridge
- D. bottom to the saddle. Discuss
- 7. Staff readings on pegs x and y from X station are 1.755 m and 2.850 m, and from station Y on staff head at Y and X are 0.655 m and 1.560 m. If reduced level of X is 105.5 m, the reduced level of Y is
Options- A. 104.0 m
- B. 104.5 m
- C. 105.0 m
- D. 105.5 m Discuss
- 8. Stadia techeometry was discovered by James Watt in the year.
Options- A. 1670
- B. 1770
- C. 1870
- D. 1900. Discuss
- 9. The correction to be applied to each 30 metre chain length along ?° slope, is
Options- A. 30 (sec ? - 1) m
- B. 30 (sin ? - 1) m
- C. 30 (cos ? - 1) m
- D. 30 (tan ? - 1) m
- E. 30 (cot ? - 1) m. Discuss
- 10. The constant vertical distance between two adjacent contours, is called
Options- A. horizontal interval
- B. horizontal equivalent
- C. vertical equivalent
- D. contour interval
- E. contour gradient. Discuss
Surveying problems
Search Results
Correct Answer: f/i
Correct Answer:
Correct Answer: back tangent and forward tangent
Correct Answer: 0.15 cm
Correct Answer: by left hand upright
Correct Answer: saddle down the hill
Correct Answer: 104.5 m
Correct Answer: 1770
Correct Answer: 30 (sec ? - 1) m
Correct Answer: contour interval
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