Discussion
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- Question
The shear force at the ends of a simply supported beam carrying a uniformly distributed load of w per unit length is
Options- A. zero at its both ends
- B. wl at one end and - wl at the other end
- C. wl/2 at one end and - wl/2 at the other end
- D. wl2/2 at one end and - wl2/2 at the other end
- Correct Answer
- wl/2 at one end and - wl/2 at the other end
- 1. The bending moment of a cantilever beam of length l and carrying a uniformly distributed load of w per unit length is __________ at the free end.
Options- A. zero
- B. wl/4
- C. wl/2
- D. wl Discuss
- 2. Shear modulus is the ratio of
Options- A. linear stress to linear strain
- B. linear stress to lateral strain
- C. volumetric strain to linear strain
- D. shear stress to shear strain Discuss
- 3. The bending stress in abeam is __________ bending moment.
Options- A. equal to
- B. less than
- C. more than
- D. directly proportional to Discuss
- 4. The Rankine's formula holds good for
Options- A. short columns
- B. long columns
- C. both short and long columns
- D. weak columns Discuss
- 5. The limit of eccentricity for no tensile conditions for a column of circular section of diameter (d) is
Options- A. d/4
- B. d/8
- C. d/12
- D. d/16 Discuss
- 6. In case of eccentrically loaded struts __________ is preferred.
Options- A. solid section
- B. hollow section
- C. composite section
- D. reinforced section Discuss
- 7. In leaf springs, the maximum bending stress developed in the plates is (where W = Load acting on the spring, l = Span of the spring, n = Number of plates, b = Width of plates, and t = Thickness of plates)
Options- A.
- B.
- C.
- D.
Discuss
- 8. The shear modulus of most materials with respect to the modulus of elasticity is
Options- A. equal to half
- B. less than half
- C. more than half
- D. none of these Discuss
- 9. The ultimate tensile stress for mild steel is __________ the ultimate compressive stress.
Options- A. equal to
- B. less than
- C. more than Discuss
- 10. In a watch, the spring is used to store strain energy. This energy is released
Options- A. to stop the watch
- B. to run the watch
- C. to change the time
- D. all of these Discuss
Strength of Materials problems
Search Results
Correct Answer: zero
Correct Answer: shear stress to shear strain
Correct Answer: directly proportional to
Correct Answer: both short and long columns
Correct Answer: d/8
Correct Answer: composite section
Correct Answer:
Correct Answer: less than half
Correct Answer: more than
Correct Answer: to run the watch
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