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Digital Electronics
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Describing Logic Circuits
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Question
Which of the figures given below represents an OR gate?
Options
A. a
B. b
C. c
D. d
Correct Answer
a
Describing Logic Circuits problems
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1. Which step in this reduction process is using DeMorgan's theorem?
Options
A. STEP 1
B. STEP 2
C. STEP 3
D. STEP 4
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Correct Answer: STEP 1
2. Identify the type of gate below from the equation
Options
A. Ex-NOR gate
B. OR gate
C. Ex-OR gate
D. NAND gate
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Correct Answer: Ex-OR gate
3. Which type of gate can be used to add two bits?
Options
A. Ex-OR
B. Ex-NOR
C. Ex-NAND
D. NOR
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Correct Answer: Ex-OR
4. The Ex-NOR is sometimes called the ________.
Options
A. parity gate
B. equality gate
C. inverted OR
D. parity gate or the equality gate
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Correct Answer: equality gate
5. Select the statement that best describes the parity method of error detection:
Options
A. Parity checking is best suited for detecting double-bit errors that occur during the transmission of codes from one location to another.
B. Parity checking is not suitable for detecting single-bit errors in transmitted codes.
C. Parity checking is best suited for detecting single-bit errors in transmitted codes.
D. Parity checking is capable of detecting and correcting errors in transmitted codes.
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Correct Answer: Parity checking is best suited for detecting single-bit errors in transmitted codes.
6. A NOR gate with one HIGH input and one LOW input:
Options
A. will output a HIGH
B. functions as an AND
C. will not function
D. will output a LOW
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Correct Answer: will output a LOW
7. What is the basic difference between AHDL and VHDL?
Options
A. ADHL is used in all PLD's.
B. VHDL is used in all PLD's.
C. ADHL is proprietary.
D. VHDL is proprietary.
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Correct Answer: ADHL is proprietary.
8. The Boolean equation for a NOR function is:
Options
A.
B.
C.
D.
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Correct Answer:
9. How are the statements between BEGIN and END not evaluated in VHDL?
Options
A. Constantly
B. Simultaneously
C. Concurrently
D. Sequentially
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Correct Answer: Sequentially
10. A NAND gate has:
Options
A. active-LOW inputs and an active-HIGH output.
B. active-LOW inputs and an active-LOW output.
C. active-HIGH inputs and an active-HIGH output.
D. active-HIGH inputs and an active-LOW output.
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Correct Answer: active-HIGH inputs and an active-LOW output.
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