logo

CuriousTab

CuriousTab

Discussion


Home Digital Electronics Number Systems and Codes Comments

  • Question
  • Assign the proper even parity bit to the code 1100001.


  • Options
  • A. 11100001
  • B. 1100001
  • C. 01100001
  • D. 01110101

  • Correct Answer
  • 11100001 


  • Number Systems and Codes problems


    Search Results


    • 1. Decode the following ASCII message.

      10100111010100101010110001001011001
      01000001001000100000110100101000100

    • Options
    • A. STUDYHARD
    • B. STUDY HARD
    • C. stydyhard
    • D. study hard
    • Discuss
    • 2. Convert the following hexadecimal number to decimal.
      B516

    • Options
    • A. 212
    • B. 197
    • C. 165
    • D. 181
    • Discuss
    • 3. The decimal number for octal 748 is ________.

    • Options
    • A. 74
    • B. 60
    • C. 22
    • D. 62
    • Discuss
    • 4. What is the resultant binary of the decimal problem 49 + 01 =?

    • Options
    • A. 01010101
    • B. 00110101
    • C. 00110010
    • D. 00110001
    • Discuss
    • 5. The binary number 101110101111010 can be written in octal as ________.

    • Options
    • A. 515628
    • B. 565778
    • C. 656278
    • D. 565728
    • Discuss
    • 6. Convert the following decimal number to octal.
      281

    • Options
    • A. 1348
    • B. 4318
    • C. 3318
    • D. 1338
    • Discuss
    • 7. Convert the following decimal number to hexadecimal.
      125

    • Options
    • A. 7D16
    • B. D716
    • C. 7C16
    • D. C716
    • Discuss
    • 8. Convert binary 11001111 to hexadecimal.

    • Options
    • A. 8F16
    • B. CE16
    • C. DF16
    • D. CF16
    • Discuss
    • 9. Determine the decimal equivalent of the signed binary number 11110100 in 1's complement.

    • Options
    • A. 116
    • B. ?12
    • C. 11
    • D. 128
    • Discuss
    • 10. Convert the following hexadecimal number to binary.
      C916

    • Options
    • A. 101110012
    • B. 101110112
    • C. 100111002
    • D. 110010012
    • Discuss


    Comments

    There are no comments.

Enter a new Comment