Discussion
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- Question
How many address lines would be required for a 2K × 4 memory chip?
Options- A. 8
- B. 10
- C. 11
- D. 12
- Correct Answer
- 11
- 1. How are the statements between BEGIN and END not evaluated in VHDL?
Options- A. Constantly
- B. Simultaneously
- C. Concurrently
- D. Sequentially Discuss
- 2. Does the 74123 one shot have an internal timing resistor?
Options- A. yes
- B. no Discuss
- 3. The Boolean expression for a three-input AND gate is X = ABC.
Options- A. True
- B. False Discuss
- 4. The schematic editor allows you to connect with predefined logic symbols.
Options- A. True
- B. False Discuss
- 5. The technique used by one-shots to respond to an edge rather than a level is called ________.
Options- A. level management
- B. edge triggering
- C. trigger input
- D. edge trapping Discuss
- 6. The address-decoding scheme for a 16K-byte EPROM memory system requires a 1-to-8-address decoder when 4K × 8 memory is used.
Options- A. True
- B. False Discuss
- 7. The original Pentium was the first CPU to feature separate data and instruction caches.
Options- A. True
- B. False Discuss
- 8. What is a disadvantage of CMOS in place of TTL?
Options- A. It switches slower.
- B. It uses less power.
- C. It is smaller.
- D. cost Discuss
- 9. Which of the following statements accurately represents the two BEST methods of logic circuit simplification?
Options- A. Boolean algebra and Karnaugh mapping
- B. Karnaugh mapping and circuit waveform analysis
- C. Actual circuit trial and error evaluation and waveform analysis
- D. Boolean algebra and actual circuit trial and error evaluation Discuss
- 10. What is the bit storage capacity of a ROM with a 1024 × 8 organization?
Options- A. 1024
- B. 2048
- C. 4096
- D. 8192 Discuss
More questions
Correct Answer: Sequentially
Correct Answer: no
Correct Answer: True
Correct Answer: True
Correct Answer: level management
Correct Answer: True
Correct Answer: True
Correct Answer: It switches slower.
Correct Answer: Boolean algebra and Karnaugh mapping
Correct Answer: 8192
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