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Home ‣ Digital Electronics ‣ Digital Arithmetic Operations and Circuits Comments
  • Question

  • Divide the following binary numbers.
    Divide the following binary numbers. 0000 0010 0000 0010 1000 1111 0000 0010 0001 0010 0000 0100 000


  • Options
  • A. 0000  0010    0000  0010    1000  1111
  • B. 0000  0010    0001  0010    0000  0100
  • C. 0000  0011    0000  0010    0000  0100
  • D. 0000  0010    0000  0010    0000  0100

  • Correct Answer
  • 0000  0010    0000  0010    0000  0100 

    • Digital Arithmetic Operations and Circuits problems

    Search Results

    • 1. In VHDL, what is a GENERATE statement?

    • Options
    • A. The start statement of a program
    • B. Not used in VHDL or ADHL
    • C. A way to get the computer to generate a program from a circuit diagram
    • D. A way to tell the compiler to replicate several components
      • Discuss
    • 2. What is the difference between a full-adder and a half-adder?

    • Options
    • A. Half-adder has a carry-in.
    • B. Full-adder has a carry-in.
    • C. Half-adder does not have a carry-out.
    • D. Full-adder does not have a carry-out.
      • Discuss
    • 3. Adding in binary, a decimal 26 + 27 will produce a sum of:

    • Options
    • A. 111010
    • B. 110110
    • C. 110101
    • D. 101011
      • Discuss
    • 4. Solve this binary problem:

    • Options
    • A. 1001
    • B. 0110
    • C. 0111
    • D. 0101
      • Discuss
    • 5. What is the correct output of the adder in the given figure, with the outputs in the order:


    • Options
    • A. 10111
    • B. 11101
    • C. 01101
    • D. 10011
      • Discuss
    • 6. An 8-bit register may provide storage for two's-complement codes within which decimal range?

    • Options
    • A. +128 to ?128
    • B. ?128 to +127
    • C. +128 to ?127
    • D. +127 to ?127
      • Discuss
    • 7. When multiplying 13 × 11 in binary, what is the third partial product?

    • Options
    • A. 1011
    • B. 00000000
    • C. 100000
    • D. 100001
      • Discuss
    • 8. Add the following BCD numbers.

      0110   0111   1001
      0101   1000   1000

    • Options
    • A. 0000  1011    0000  1111    0001  0001
    • B. 0001  0001    0001  0101    0001  0001
    • C. 0000  1011    0000  1111    0001  0111
    • D. 0001  0001    0001  0101    0001  0111
      • Discuss
    • 9. Could the sum output of a full-adder be used as a two-bit parity generator?

    • Options
    • A. Yes
    • B. No
      • Discuss
    • 10. Perform the following hex subtraction: ACE16 ? 99916 =

    • Options
    • A. 23516
    • B. 13516
    • C. 03516
    • D. 33516
      • Discuss

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