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Home Digital Electronics Boolean Algebra and Logic Simplification Comments

  • Question
  • Which of the following combinations cannot be combined into K-map groups?


  • Options
  • A. corners in the same row
  • B. corners in the same column
  • C. diagonal
  • D. overlapping combinations

  • Correct Answer
  • diagonal 


  • Boolean Algebra and Logic Simplification problems


    Search Results


    • 1. Determine the binary values of the variables for which the following standard POS expression is equal to 0.

    • Options
    • A. (0 + 1 + 0)(1 + 0 + 1)
    • B. (1 + 1 + 1)(0 + 0 + 0)
    • C. (0 + 0 + 0)(1 + 0 + 1)
    • D. (1 + 1 + 0)(1 + 0 + 0)
    • Discuss
    • 2. Mapping the standard SOP expression , we get


    • Options
    • A. (A)
    • B. (B)
    • C. (C)
    • D. (D)
    • Discuss
    • 3. Use Boolean algebra to find the most simplified SOP expression for F = ABD + CD + ACD + ABC + ABCD.

    • Options
    • A. F = ABD + ABC + CD
    • B. F = CD + AD
    • C. F = BC + AB
    • D. F = AC + AD
    • Discuss
    • 4. Mapping the SOP expression , we get ________.


    • Options
    • A. (A)
    • B. (B)
    • C. (C)
    • D. (D)
    • Discuss
    • 5. AC + ABC = AC

    • Options
    • A. True
    • B. False
    • Discuss
    • 6. From the truth table below, determine the standard SOP expression.


    • Options
    • A.
    • B.
    • C.
    • D.
    • Discuss
    • 7. Which output expression might indicate a product-of-sums circuit construction?

    • Options
    • A.
    • B.
    • C.
    • D.
    • Discuss
    • 8. The expression W(X + YZ) can be converted to SOP form by applying which law?

    • Options
    • A. associative law
    • B. commutative law
    • C. distributive law
    • D. none of the above
    • Discuss
    • 9. One of De Morgan's theorems states that . Simply stated, this means that logically there is no difference between:

    • Options
    • A. a NOR and an AND gate with inverted inputs
    • B. a NAND and an OR gate with inverted inputs
    • C. an AND and a NOR gate with inverted inputs
    • D. a NOR and a NAND gate with inverted inputs
    • Discuss
    • 10. Implementing the expression AB + CDE using NAND logic, we get:


    • Options
    • A. (A)
    • B. (B)
    • C. (C)
    • D. (D)
    • Discuss


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