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- Question
The selector inputs to an arithmetic-logic unit (ALU) determine the:
Options- A. selection of the IC
- B. arithmetic or logic function
- C. data word selection
- D. clock frequency to be used
- Correct Answer
- arithmetic or logic function
- 1. When 1100010 is divided by 0101, what will be the decimal remainder?
Options- A. 2
- B. 3
- C. 4
- D. 6 Discuss
- 2. The two's complement system is to be used to add the signed numbers 11110010 and 11110011. Determine, in decimal, the sign and value of each number and their sum.
Options- A. ?14 and ?13; ?27
- B. ?113 and ?114; 227
- C. ?27 and ?13; 40
- D. ?11 and ?16; ?27 Discuss
- 3. Adding in binary, the decimal values 26 + 27 will produce a sum of:
Options- A. 111010
- B. 110110
- C. 110101
- D. 101011 Discuss
- 4. The fast carry or look-ahead carry circuits found in most 4-bit parallel-adder circuits:
Options- A. increase ripple delay
- B. add a 1 to complemented inputs
- C. reduce propagation delay
- D. determine sign and magnitude Discuss
- 5. Adding the two's complement of ?11 + (?2) will yield which two's complement answer?
Options- A. 1110 1101
- B. 1111 1001
- C. 1111 0011
- D. 1110 1001 Discuss
- 6. Binary subtraction of a decimal 15 from 43 will utilize which two's complement?
Options- A. 101011
- B. 110000
- C. 011100
- D. 110001 Discuss
- 7. What are the two types of basic adder circuits?
Options- A. half adder and full adder
- B. half adder and parallel adder
- C. asynchronous and synchronous
- D. one's complement and two's complement Discuss
- 8. When multiplying in binary the decimal values 13 × 11, what is the third partial product?
Options- A. 100000
- B. 100001
- C. 0000
- D. 1011 Discuss
- 9. The range of an 8-bit two's complement word is from:
Options- A. +12810 to ?12810
- B. ?12810 to +12710
- C. +12810 to ?12710
- D. +12710 to ?12710 Discuss
- 10. How many basic binary subtraction operations are possible?
Options- A. 4
- B. 3
- C. 2
- D. 1 Discuss
Arithmetic Operations and Circuits problems
Search Results
Correct Answer: 3
Correct Answer: ?14 and ?13; ?27
Correct Answer: 110101
Correct Answer: reduce propagation delay
Correct Answer: 1111 0011
Correct Answer: 110001
Correct Answer: half adder and full adder
Correct Answer: 100000
Correct Answer: ?12810 to +12710
Correct Answer: 1
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