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- Question
What is the purpose of fflush() function.
Options- A. flushes all streams and specified streams.
- B. flushes only specified stream.
- C. flushes input/output buffer.
- D. flushes file buffer.
- Correct Answer
- flushes all streams and specified streams.
Explanation"fflush()" flush any buffered output associated with filename, which is either a file opened for writing or a shell command for redirecting output to a pipe or coprocess.
Example:
fflush(FilePointer);
fflush(NULL); flushes all streams.
More questions
- 1. va_list is an array that holds information needed by va_arg and va_end
Options- A. True
- B. False Discuss
Correct Answer: True
- 2. A structure can contain similar or dissimilar elements
Options- A. True
- B. False Discuss
Correct Answer: True
- 3. Which of the statements is correct about the program?
#include<stdio.h> int main() { float a=3.14; char *j; j = (char*)&a; printf("%d\n", *j); return 0; }
Options- A. It prints ASCII value of the binary number present in the first byte of a float variable a.
- B. It prints character equivalent of the binary number present in the first byte of a float variable a.
- C. It will print 3
- D. It will print a garbage value Discuss
Correct Answer: It prints ASCII value of the binary number present in the first byte of a float variable a.
- 4. What will be the output of the program?
#include<stdio.h> int main() { int i=4; switch(i) { default: printf("This is default\n"); case 1: printf("This is case 1\n"); break; case 2: printf("This is case 2\n"); break; case 3: printf("This is case 3\n"); } return 0; }
Options- A. This is default
This is case 1 - B. This is case 3
This is default - C. This is case 1
This is case 3 - D. This is default Discuss
Correct Answer: This is default
This is case 1
Explanation:
In the very begining of switch-case statement default statement is encountered. So, it prints "This is default".In default statement there is no break; statement is included. So it prints the case 1 statements. "This is case 1".
Then the break; statement is encountered. Hence the program exits from the switch-case block.
- 5. What will be the output of the program?
#include<stdio.h> int main() { int a = 300, b, c; if(a >= 400) b = 300; c = 200; printf("%d, %d, %d\n", a, b, c); return 0; }
Options- A. 300, 300, 200
- B. Garbage, 300, 200
- C. 300, Garbage, 200
- D. 300, 300, Garbage Discuss
Correct Answer: 300, Garbage, 200
Explanation:
Step 1: int a = 300, b, c; here variable a is initialized to '300', variable b and c are declared, but not initialized.
Step 2: if(a >= 400) means if(300 >= 400). Hence this condition will be failed.
Step 3: c = 200; here variable c is initialized to '200'.
Step 4: printf("%d, %d, %d\n", a, b, c); It prints "300, garbage value, 200". because variable b is not initialized.- 6. What will be the output of the program?
#include<stdio.h> int main() { int x = 10, y = 20; if(!(!x) && x) printf("x = %d\n", x); else printf("y = %d\n", y); return 0; }
Options- A. y =20
- B. x = 0
- C. x = 10
- D. x = 1 Discuss
Correct Answer: x = 10
Explanation:
The logical not operator takes expression and evaluates to true if the expression is false and evaluates to false if the expression is true. In other words it reverses the value of the expression.Step 1: if(!(!x) && x)
Step 2: if(!(!10) && 10)
Step 3: if(!(0) && 10)
Step 3: if(1 && 10)
Step 4: if(TRUE) here the if condition is satisfied. Hence it prints x = 10.- 7. Which of the following correctly represents a long double constant?
Options- A. 6.68
- B. 6.68L
- C. 6.68f
- D. 6.68LF Discuss
Correct Answer: 6.68L
Explanation:
6.68 is double.
6.68L is long double constant.
6.68f is float constant.
6.68LF is not allowed in c.
- 8. What will be the output of the program?
#include<stdio.h> int main() { enum status {pass, fail, absent}; enum status stud1, stud2, stud3; stud1 = pass; stud2 = absent; stud3 = fail; printf("%d %d %d\n", stud1, stud2, stud3); return 0; }
Options- A. 0, 1, 2
- B. 1, 2, 3
- C. 0, 2, 1
- D. 1, 3, 2 Discuss
Correct Answer: 0, 2, 1
- 9. Point out the error in the program?
#include<stdio.h> int main() { struct emp { char name[20]; float sal; }; struct emp e[10]; int i; for(i=0; i<=9; i++) scanf("%s %f", e[i].name, &e[i].sal); return 0; }
Options- A. Error: invalid structure member
- B. Error: Floating point formats not linked
- C. No error
- D. None of above Discuss
Correct Answer: Error: Floating point formats not linked
Explanation:
At run time it will show an error then program will be terminated.Sample output: Turbo C (Windows)
c:\>myprogram Sample 12.123 scanf : floating point formats not linked Abnormal program termination- 10. If the following structure is written to a file using fwrite(), can fread() read it back successfully?
struct emp { char *n; int age; }; struct emp e={"CuriousTab", 15}; FILE *fp; fwrite(&e, sizeof(e), 1, fp);
Options- A. Yes
- B. No Discuss
Correct Answer: No
Explanation:
Since the structure contain a char pointer while writing the structure to the disk using fwrite() only the value stored in pointer n will get written. so fread() fails to read.
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