#include<stdio.h> int main() { const int i=0; printf("%d\n", i++); return 0; }
Step 1: const int i=0; The constant variable 'i' is declared as an integer and initialized with value of '0'(zero).
Step 2: printf("%d\n", i++); Here the variable 'i' is increemented by 1(one). This will create an error "Cannot modify a const object".
Because, we cannot modify a const variable.
struct emp { int ecode; struct emp *e; };
#include<stdio.h> int main() { union a { int i; char ch[2]; }; union a z1 = {512}; union a z2 = {0, 2}; return 0; }
struct emp { int ecode; struct emp e; };
/* sample.c */ #include<stdio.h> int main(int argc, char *argv[]) { printf("%c", **++argv); return 0; }
#include<stdio.h> int main() { char far *near *ptr1; char far *far *ptr2; char far *huge *ptr3; printf("%d, %d, %d\n", sizeof(ptr1), sizeof(ptr2), sizeof(ptr3)); return 0; }
#include<stdio.h> int main() { char huge *near *far *ptr1; char near *far *huge *ptr2; char far *huge *near *ptr3; printf("%d, %d, %d\n", sizeof(ptr1), sizeof(*ptr2), sizeof(**ptr3)); return 0; }
#include<stdio.h> typedef void v; typedef int i; int main() { v fun(i, i); fun(2, 3); return 0; } v fun(i a, i b) { i s=2; float i; printf("%d,", sizeof(i)); printf(" %d", a*b*s); }
/* myprog.c */ #include<stdio.h> #include<stdlib.h> int main(int argc, char **argv) { int i, j=0; for(i=0; i<argc; i++) j = j+atoi(argv[i]); printf("%d\n", j); return 0; }
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.