What will be the output of the program? #include int main() { const c = -11; const int d = 34; printf("%d, %d ", c, d); return 0; }

Question

What will be the output of the program? #include<stdio.h>

int main()
{
    const c = -11;
    const int d = 34;
    printf("%d, %d
", c, d);
    return 0;
}

Accepted Answer

Step 1: const c = -11; The constant variable 'c' is declared and initialized to value "-11".

Step 2: const int d = 34; The constant variable 'd' is declared as an integer and initial…

What will be the output of the program? #include<stdio.h> int main() { const c = -11; const int d = 34; printf("%d, %d\n", c, d); return 0; }

Discussion & Comments