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- Question
If a variable is a pointer to a structure, then which of the following operator is used to access data members of the structure through the pointer variable?
Options- A. .
- B. &
- C. *
- D. ->
- Correct Answer
- ->
- 1. If an unsigned int is 2 bytes wide then, What will be the output of the program?
#include<stdio.h> int main() { unsigned int a=0xffff; ~a; printf("%x\n", a); return 0; }
Options- A. ffff
- B. 0000
- C. 00ff
- D. ddfd Discuss
- 2. Declare the following statement?
"A pointer to an array of three chars".
Options- A.
char *ptr[3](); - B.
char (*ptr)*[3]; - C.
char (*ptr[3])(); - D.
char (*ptr)[3];
Discuss
- 3. What will be the output of the program?
#include<stdio.h> int main() { unsigned int res; res = (64 >>(2+1-2)) & (~(1<<2)); printf("%d\n", res); return 0; }
Options- A. 32
- B. 64
- C. 0
- D. 128 Discuss
- 4. Union elements can be of different sizes.
Options- A. True
- B. False Discuss
- 5. What will be the output of the program in DOS (Compiler - Turbo C)?
#include<stdio.h> double i; int main() { (int)(float)(char) i; printf("%d",sizeof(i)); return 0; }
Options- A. 4
- B. 8
- C. 16
- D. 22 Discuss
- 6. size of union is size of the longest element in the union
Options- A. Yes
- B. No Discuss
- 7. Bitwise & can be used to divide a number by powers of 2
Options- A. True
- B. False Discuss
- 8. Assuming, integer is 2 byte, What will be the output of the program?
#include
; int main() { printf("%x\n", -1>>1); return 0; }
Options- A. ffff
- B. 0fff
- C. 0000
- D. fff0 Discuss
- 9. What is the output of the program given below?
#include<stdio.h> int main() { enum status { pass, fail, atkt}; enum status stud1, stud2, stud3; stud1 = pass; stud2 = atkt; stud3 = fail; printf("%d, %d, %d\n", stud1, stud2, stud3); return 0; }
Options- A. 0, 1, 2
- B. 1, 2, 3
- C. 0, 2, 1
- D. 1, 3, 2 Discuss
- 10. What will be the output of the program?
#include<stdio.h> int main() { char ch; ch = 'A'; printf("The letter is"); printf("%c", ch >= 'A' && ch <= 'Z'? ch + 'a' - 'A':ch); printf("Now the letter is"); printf("%c\n", ch >= 'A' && ch <= 'Z'? ch : ch + 'a' - 'A'); return 0; }
Options- A. The letter is a
Now the letter is A - B. The letter is A
Now the letter is a - C. Error
- D. None of above Discuss
More questions
Correct Answer: ffff
Correct Answer:
char (*ptr)[3];Correct Answer: 32
Correct Answer: True
Correct Answer: 8
Correct Answer: Yes
Correct Answer: False
Correct Answer: ffff
Explanation:
1's complement: Inverting the bits ( all 1s to 0s and all 0s to 1s)
2's complement: Adding 1 to the result of 1's complement.
Binary of 1(2byte) : 0000 0000 0000 0001 Representing -1: 1s complement of 1(2byte) : 1111 1111 1111 1110 Adding 1 to 1's comp. result : 1111 1111 1111 1111 Right shift 1bit(-1>>1): 1111 1111 1111 1111 (carry out 1) Hexadecimal : f f f f (Filled with 1s in the left side in the above step)Note:
1. Fill with 1s in the left side for right shift for negative numbers.
2. Fill with 0s in the right side for left shift for negative numbers.
3. Fill with 0s in the left side for right shift for positive numbers.
4. Fill with 0s in the right side for left shift for positive numbers.
Correct Answer: 0, 2, 1
Explanation:
stud1 = pass (value is 0)
stud2 = atkt (value is 2)
stud3 = fail (value is 1)
Hence it prints 0, 2, 1
Correct Answer: The letter is a
Now the letter is A
Explanation:
Step 2: printf("The letter is"); It prints "The letter is".
Step 3: printf("%c", ch >= 'A' && ch <= 'Z' ? ch + 'a' - 'A':ch);
The ASCII value of 'A' is 65 and 'a' is 97.
Here
=> ('A' >= 'A' && 'A' <= 'Z') ? (A + 'a' - 'A'):('A')
=> (TRUE && TRUE) ? (65 + 97 - 65) : ('A')
=> (TRUE) ? (97): ('A')
In printf the format specifier is '%c'. Hence prints 97 as 'a'.
Step 4: printf("Now the letter is"); It prints "Now the letter is".
Step 5: printf("%c\n", ch >= 'A' && ch <= 'Z' ? ch : ch + 'a' - 'A');
Here => ('A' >= 'A' && 'A' <= 'Z') ? ('A') : (A + 'a' - 'A')
=> (TRUE && TRUE) ? ('A') :(65 + 97 - 65)
=> (TRUE) ? ('A') : (97)
It prints 'A'
Hence the output is
The letter is a
Now the letter is A
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