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- Question
Which of the following is the correct order if calling functions in the below code?
a = f1(23, 14) * f2(12/4) + f3();
Options- A. f1, f2, f3
- B. f3, f2, f1
- C. Order may vary from compiler to compiler
- D. None of above
- Correct Answer
- Order may vary from compiler to compiler
ExplanationHere, Multiplication will happen before the addition, but in which order the functions would be called is undefined. In an arithmetic expression the parenthesis tell the compiler which operands go with which operators but do not force the compiler to evaluate everything within the parenthesis first. - 1. What will be the output of the program under DOS?
#include<stdio.h> int main() { char huge *near *far *ptr1; char near *far *huge *ptr2; char far *huge *near *ptr3; printf("%d, %d, %d\n", sizeof(ptr1), sizeof(**ptr2), sizeof(ptr3)); return 0; }
Options- A. 4, 4, 4
- B. 4, 2, 2
- C. 2, 8, 4
- D. 2, 4, 8 Discuss
- 2. What will be the output of the program?
#include<stdio.h> #define SQR(x)(x*x) int main() { int a, b=3; a = SQR(b+2); printf("%d\n", a); return 0; }
Options- A. 25
- B. 11
- C. Error
- D. Garbage value Discuss
- 3. Point out the error in the program.
#include<stdio.h> const char *fun(); int main() { *fun() = 'A'; return 0; } const char *fun() { return "Hello"; }
Options- A. Error: RValue required
- B. Error: Lvalue required
- C. Error: fun() returns a pointer const character which cannot be modified
- D. No error Discuss
- 4. Which statement will you add to the following program to ensure that the program outputs "CuriousTab" on execution?
#include<stdio.h> int main() { char s[] = "CuriousTab"; char t[25]; char *ps, *pt; ps = s; pt = t; while(*ps) *pt++ = *ps++; /* Add a statement here */ printf("%s\n", t); return 0; }
Options- A. *pt='';
- B. pt='\0';
- C. pt='\n';
- D. *pt='\0'; Discuss
- 5. A float occupies 4 bytes. If the hexadecimal equivalent of these 4 bytes are A, B, C and D, then when this float is stored in memory in which of the following order do these bytes gets stored?
Options- A. ABCD
- B. DCBA
- C. 0xABCD
- D. Depends on big endian or little endian architecture Discuss
- 6. To print out a and b given below, which of the following printf() statement will you use?
#include<stdio.h> float a=3.14; double b=3.14;
Options- A. printf("%f %lf", a, b);
- B. printf("%Lf %f", a, b);
- C. printf("%Lf %Lf", a, b);
- D. printf("%f %Lf", a, b); Discuss
- 7. Which of the following function is more appropriate for reading in a multi-word string?
Options- A. printf();
- B. scanf();
- C. gets();
- D. puts(); Discuss
- 8. What will be the output of the program if the array begins at address 65486?
#include<stdio.h> int main() { int arr[] = {12, 14, 15, 23, 45}; printf("%u, %u\n", arr, &arr); return 0; }
Options- A. 65486, 65488
- B. 65486, 65486
- C. 65486, 65490
- D. 65486, 65487 Discuss
- 9. What will be the output of the program in Turbo C (under DOS)?
#include<stdio.h> int main() { struct emp { char *n; int age; }; struct emp e1 = {"Dravid", 23}; struct emp e2 = e1; strupr(e2.n); printf("%s\n", e1.n); return 0; }
Options- A. Error: Invalid structure assignment
- B. DRAVID
- C. Dravid
- D. No output Discuss
- 10. Does there any function exist to convert the int or float to a string?
Options- A. Yes
- B. No Discuss
More questions
Correct Answer: 4, 2, 2
Correct Answer: 11
Explanation:
The macro function SQR(x)(x*x) calculate the square of the given number 'x'. (Eg: 102)
Step 1: int a, b=3; Here the variable a, b are declared as an integer type and the variable b is initialized to 3.
Step 2: a = SQR(b+2); becomes,
=> a = b+2 * b+2; Here SQR(x) is replaced by macro to x*x .
=> a = 3+2 * 3+2;
=> a = 3 + 6 + 2;
=> a = 11;
Step 3: printf("%d\n", a); It prints the value of variable 'a'.
Hence the output of the program is 11
Correct Answer: Error: fun() returns a pointer const character which cannot be modified
Correct Answer: *pt='\0';
Correct Answer: Depends on big endian or little endian architecture
Correct Answer: printf("%f %lf", a, b);
Explanation:
To print a float value, %f is used as format specifier.
To print a double value, %lf is used as format specifier.
Therefore, the answer is printf("%f %lf", a, b);
Correct Answer: gets();
Explanation:
gets(); collects a string of characters terminated by a new line from the standard input stream stdin
#include <stdio.h>
int main(void)
{
char string[80];
printf("Enter a string:");
gets(string);
printf("The string input was: %s\n", string);
return 0;
}
Output:
Enter a string: CuriousTab
The string input was: CuriousTab
Correct Answer: 65486, 65486
Explanation:
Step 1: int arr[] = {12, 14, 15, 23, 45}; The variable arr is declared as an integer array and initialized.
Step 2: printf("%u, %u\n", arr, &arr); Here,
The base address of the array is 65486.
=> arr, &arr is pointing to the base address of the array arr.
Hence the output of the program is 65486, 65486
Correct Answer: DRAVID
Correct Answer: Yes
Explanation:
1. itoa() converts an integer to a string.
2. ltoa() converts a long to a string.
3. ultoa() converts an unsigned long to a string.
4. sprintf() sends formatted output to a string, so it can be used to convert any type of values to string type.
2. ltoa() converts a long to a string.
3. ultoa() converts an unsigned long to a string.
4. sprintf() sends formatted output to a string, so it can be used to convert any type of values to string type.
#include<stdio.h>
#include<stdlib.h>
int main(void)
{
int num1 = 12345;
float num2 = 5.12;
char str1[20];
char str2[20];
itoa(num1, str1, 10); /* 10 radix value */
printf("integer = %d string = %s \n", num1, str1);
sprintf(str2, "%f", num2);
printf("float = %f string = %s", num2, str2);
return 0;
}
// Output:
// integer = 12345 string = 12345
// float = 5.120000 string = 5.120000
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