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What will be the output of the program? #include int main() { int x=12, y=7, z; z = x!=4 || y == 2; printf("z=%d\n", z); return 0; }

Correct Answer: z=1

Explanation:

Step 1: int x=12, y=7, z; here variable x, y and z are declared as an integer and variable x and y are initialized to 12, 7 respectively.


Step 2: z = x!=4 || y == 2;
becomes z = 12!=4 || 7 == 2;
then z = (condition true) || (condition false); Hence it returns 1. So the value of z=1.


Step 3: printf("z=%d\n", z); Hence the output of the program is "z=1".


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