A broadside array operating at 100 cm wavelength consist of 4 half-wave dipoles spaced 50 cm apart. Each element carries radio frequency current in the same phase and of magnitude 0.5 A. The radiated power will be
Options
A. 196 W
B. 73 W
C. 36.5 W
D. 18.25 W
Correct Answer
196 W
Explanation
P = n . I2 . Rr, where Rr = 80p2 ?.
n = 4.
Electromagnetic Field Theory problems
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1. The divergence of the electric field intensity at any point equals
Options
A. 1/4 p?0 times the volume charge density
B. l/?0 times the volume charge density at that point
C. ?0 times the volume charge density at that point
Correct Answer: l/?0 times the volume charge density at that point
Explanation:
2. Radiation intensity of a dipole depends strongly on frequency. If at a frequency f, the intensity of radiation is 'I'. Then at a frequency of f/2, the intensity will be
3. The Depth of penetration of EM wave in medium having conductivity ? at a frequency of 1 MHz is 25 cm. The depth of penetration at a frequency of 4 MHz will be
6. A rectangular metal waveguide filled with a dielectric of relative permittivity ?r = 4, has the inside dimensions 3 x 1.2 cm, the cut off frequency for the dominant mode is
7. Two identical antennas are placed in the ? = p/2 plane as shown in the figure. The elements have equal amplitude excitation with 180° polarity difference, operating of the far-zone resultant electric field strength normalized with that of a single element, both computed for ? = 0, is
9. A broadside array consisting of 200 cm wavelength with 10 half-wave dipole spacing 10 cm. And if each array element feeding with 1 amp. current and operating at same frequency then find the half power beamwidth