The electric field on the surface of a perfect conductor is 2V/m. The conductor is immersed in water with ε = 80 ε0. The surface charge density on the conductor is ((ε0 = 10-9/36p)F/m)

• 0 c/m2
• 2 c/m2
• 1.8 x 10-11 c/m2
• 1.14 x 10-9 c/m2

Correct Answer: 1.14 x 10-9 c/m2

Explanation:

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