(A + B + C) (A + B + C) (A + B + C).
Here,
a = 1.59'' = 40.386 mm = 4.04 cm
? .
Power gain = 10
Thus directivity .
= 2H log2 V bits/sec
V - discrete levels (Here Binary i.e. 2)
H - Bandwidth
? Maximum data rate = 2H log2 V
= 2(3 KHz) log2 2 = 2 x 3 x 103 x 1
= 6 x 103 = 6000 bps.
? VP = 3.46 x 108 m/s.
Number of samples per period = 10p
This is not a rational number. Hence signal is non periodic.
The area of the shaded region
.
F1 > F2 > F3
j = light intensity = constant
Photocurrent Vs Anode voltage with frequency and incident light as a parameter.
The light intensity is constant.
Then number of bits are '4'
Resolution
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