L1 = be, L2 = cf, L3 = dg
?1 = 1
.
m = 0.8
= 8 x 1.149 = 9.19 A.
f2(A, B, C, D) = ?(3, 6, 7)
f1 ? f2 = ?(3, 13, 14)
f3 x (f1 ? f2) = ?(14) = y
X = f1 x y ? ?14.
to get apply aebxdx + ae-bxdx,
we get = .
L = B - N + 1
where L : No. of loop equations
B : No. of branches = 12
N : No. of nodes = 8
L = 12 - 8 + 1 = 5.
Overall voltage gain will decrease as feedback signal comes into picture and since it is current-series feedback, input impedance increases.
AC cos?ct
for envelope detection ? < 1 ? < 1 ? Ac should be at least-2.
.
n = 8
Thus (SNR)dB = 1.76 + 6.02 x 8 = 49.92 dB.
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