Let ten's and unit's digits be 2x and x respectively.
Then, (10 x 2x + x) - (10x + 2x) = 36
⟹ 9x = 36
⟹ x = 4.
∴ Required difference = (2x + x) - (2x - x) = 2x = 8.
Then, xy = 120 and x2 + y2 = 289.
∴ (x + y)2 = x2 + y2 + 2xy = 289 + (2 x 120) = 529
∴ x + y = √529 = 23.
Then, 3x = 2(x + 4) + 3 ⟺ x = 11.
∴ Third integer = x + 4 = 15.
Then, | 1 | of | 1 | of x = 15 ⟺ x = 15 x 3 x 4 = 180. |
3 | 4 |
So, required number = | ❨ | 3 | x 180 | ❩ | = 54. |
10 |
Then, x + y = 15 and x - y = 3 or y - x = 3.
Solving x + y = 15 and x - y = 3, we get: x = 9, y = 6.
Solving x + y = 15 and y - x = 3, we get: x = 6, y = 9.
So, the number is either 96 or 69.
Hence, the number cannot be determined.
Then, (10x + y) - (10y + x) = 36
⟹ 9(x - y) = 36
⟹ x - y = 4.
Then, a2 + b2 + c2 = 138 and (ab + bc + ca) = 131.
(a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca) = 138 + 2 x 131 = 400.
⟹ (a + b + c) = √400 = 20.
Then, x + 17 = | 60 |
x |
⟹ x2 + 17x - 60 = 0
⟹ (x + 20)(x - 3) = 0
⟹ x = 3.
Then, (x + 2)2 - x2 = 84
⟹ 4x + 4 = 84
⟹ 4x = 80
⟹ x = 20.
∴ The required sum = x + (x + 2) = 2x + 2 = 42.
4.036 | = | 403.6 | = 100.9 |
0.04 | 4 |
The value of | (0.96)3 - (0.1)3 | is: |
(0.96)2 + 0.096 + (0.1)2 |
Given expression |
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