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- Question
What would be the output of the following program? main() { extern int i; i = 20; printf( "%d", sizeof(i) ); }
- Correct Answer
- extern int i is a declaration and not a definition, hence Error occured
- 1. The output of the code below is #include
int *m() { int *p = 5; return p; } void main() { int *k = m(); printf("%d", k); }
Options- A. 5
- B. Junk value
- C. 0
- D. Error Discuss
- 2. What is the output of this C code? #include
void m() { printf("hi"); } void main() { m(); }
Options- A. hi
- B. Run time error
- C. None
- D. Varies Discuss
- 3. What will be output of following c code? void main() { struct india { char c; float d; }; struct world { int a[3]; char b; struct india orissa; }; struct world st ={{1,2,3},'P','q',1.4}; clrscr(); printf("%dt%ct%ct%f",st.a[1],st.b,st.orissa.c,st.orissa.d); getch(); } Discuss
- 4. Write a c program to copy a data of file to other file. Discuss
- 5. Write a program for matrix multiplication in c Discuss
- 6. What is the difference between the following declarations? extern int fun(); int fun(); Discuss
- 7. Point out the error, if any, in the following program. main() { int ( *p )() = fun; ( *P ) (); } fun () { Printf ( "\nLoud and clear" ); } Discuss
- 8. Point out the error, if any, in the while loop. main() { int i = 1; while () { printf ( "%d", i++); if (i >10) break ; } } Discuss
- 9. Point out the error, if any, in the following program. main() { int i = 4, j = 2; switch(i) { case 1 : printf (''\n To err is human, to forgive is against company policy."); break; case j : printf (''\n if you have nothing to do, don't do it here."); break; } } Discuss
- 10. What would be the output of the following program? main() { static int a[20]; int i = 0; a[i] = i++; printf ("\n%d%d%d", a[0], a[1], i); } Discuss
Programming problems
Search Results
Correct Answer: 5
Correct Answer: hi
Correct Answer: Output: 2 p q 1400000
Correct Answer: #include
Correct Answer: #include
Correct Answer: There is no difference except for the fact that the first one gives a hint that the function fun() is probably in another source file
Correct Answer: Here we are initalising the function pointer p to the address of the function fun() But during this initialisation the function has not been defined Hence an error To eliminate this error add the prototype of the fun() before declaration of p, as shown below: extern int fun(); or simply int fun();
Correct Answer: The condition in the while loop is a must
Correct Answer: Constant expression required in the second case, we cannot use j
Correct Answer: 0 0 1 That's what some of the compilers would give But some other compiler may give a different answer The reason is, when a single expression causes the same object to be modified and then inspected the behaviour is undefined
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