What would be the output of the following program? main() { static int a[20]; int i = 0; a[i] = i++; printf ("\n%d%d%d", a[0], a[1], i); }

Correct Answer: 0 0 1 That's what some of the compilers would give But some other compiler may give a different answer The reason is, when a single expression causes the same object to be modified and then inspected the behaviour is undefined