How would you eliminate the warning generated on complaining the following program? main() { char far *scr; scr = 0xB8000000; *scr = 'A'; }

Correct Answer: An error would be reported in the statement k++ since arithmetic on void pointers is not permitted unless the void pointer is appropriately typecasted

Correct Answer: 65486 65486

Correct Answer: #include "dosh" main() { Char far *scr = ( char far *) 0xB8000000; Char *seg, *off; Seg = (char *) FP_SEG ( scr ); Off = ( char *) FP_OFF ( scr ); }

Correct Answer: Final

Explanation:

Once a method declared as Final cannot be  overriden

Correct Answer: It is NOT appropriate to use assertions to validate command-line arguments

Explanation:

A is incorrect. It is acceptable to use assertions to test the arguments of private methods.

 

B is incorrect. While assertion errors can be caught, Sun discourages you from doing so.

Correct Answer: 1 2

Correct Answer: A typedef defines a new name for a type, and in simpler cases like the one shown below you can define a new structure type and a typedef for it at the same time typedef struct { char name[20]; int age; } emp; However, in the structure defined in this question, there is an error because a typedef declaration cannot be used until it is defined In the given code fragment the typedef declaration is not yet defined at he point where the link field is declared

Correct Answer: No, since the structure contains a char pointer while writing the structure to the disk using fwrite() only the value stored in the pointer n would get written When this structure is read back the address would be read back but it is quite unlikely that the desired string would be present at this address in memory

Correct Answer: DRAVID When a structure is assigned, passed, or returned, the copying is done monolithically This means that the copies of any pointer fields will point to the same place as the original In other words, anything pointed to is not copied Hence, on changing the name through e2n it automatically changed e1n

Correct Answer: struct emp { char n[20]; int age; }; main() { struct emp e1 = {"Dravid", 23}; struct emp e2; scanf ("%s %d",e2n, & e2age); if( structcmp (e1,e2) ==0) printf ("The structures are equal"); else printf ("The structures are unequal"); } structcmp ( struct emp x, struct emp y) { if (strcmp (xn,yn) ==0) if (xage == yage) return (0); return (1); } In short, if you nee to compare two structures, you'll have to write your own function to do so which carries out the comparison field by field