The given number series 9, 19, 21, 43, 45, ... follows a pattern that
ALternately (x 2 + 1) and (x 1 + 2)
9
9 x 2 + 1 = 19
19 x 1 + 2 = 21
21 x 2 + 1 = 43
43 x 1 + 2 = 45
45 x 2 + 1 = 91
Hence, the next number in the given sequence is 91.
The pattern in the given series is +4, +9, +16, +25, ... i.e.
The next number is 284+25 = 309.
Here 'bccb' repeated 3 times.
b c c b | b c c b | b c c b
First difference is 6 and second is 12. But if we take third as 18, then fourth difference will be 24. Then 93 can not be the last term.
So we have to take the difference as 6, 12, 24 and 48.
So Answer is 21+24 = 45
The pattern is *2,*5/2,*2,*5/2,*2, . . . . .
So missing term is 50*(5/2)=125
The pattern is +0.05,+0.1,+0.15, . . . .
so missing term =1.8+0.20=2.0
The given number series is 22, 11, 33, 16.5, 49.5, ?
22
22 / 2 = 11
11 x 3 = 33
33 / 2 = 16.5
16.5 x 3 = 49.5
49.5 / 2 = 24.75
Hence, the next number series is 24.75.
The given number series 11, 12.2, 14.6, 18.2, ?
11
11 + 1.2 = 12.2
12.2 + 2.4 = 14.6
14.6 + 3.6 = 18.2
18.2 + 4.8 = 23
Hence, the next number in the given number series is 23.
The given number series is 10, 6, 8, 15, ?
10
10 x 0.5 + 1 = 6
6 x 1 + 2 = 8
8 x 1.5 + 3 = 15
15 x 2 + 4 = 34
Hence, the next number in the given series is 34.
The correct pattern is +9,-7,+5,-3,+1
So,85 is wrong term and must be replaced by 90-3=87
The sequence consists of two series (Y, T, O) and (B, G, ?). The first series consists of 2nd, 7th and 12th letters from the end of English alphabet. The second series consists of 2nd, 7th and 12th letters from the beginning of English alphabet.
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