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  • Question
  • Five farmers have 7,9,11,13 & 14 apple trees respectively in their orchards. Last year each of them discovered that every tree in their own orchard yields exactly the same number of apples. Further, if the 3rd farmer gives one apple to the 1st and the 5th gives 3 to each of the 2nd & d 4th, they would all exactly have the same number of apples, what were the yields per tree in the orchards of the 3rd & 4th farmers ?


  • Options
  • A. 17 & 9
  • B. 9 & 11
  • C. 9 & 9
  • D. 11 & 9

  • Correct Answer
  • 11 & 9 

    Explanation

    Let the number of apples in each tree of the 5 farmers be a, b, c, d,e respectively. Therefore total no of apples are 7a, 9b, 11c, 13d and 14e respectively.

    Given,
    7a+1 = 9b+3 = 11c-1 = 13d+3 = 14e-6 = x

    9b+3 = 13d+3
    ===> 9b = 13d
    so take b = 13 and d = 9

    9b+3 = 9*13+3 = 120
    ie, x=120

    substituting
    7a+1 = 120
    7a = 119
    a = 17

    11c-1 = 120
    11c = 121
    c=11

    14e-6 = 120
    14e = 126
    e = 9

    Yields per tree in the orchards of d 3rd & 4th farmers= 11,9

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