To solve the problem, let's define the prices and quantities of the different varieties of tea being mixed.
Given:
Let the price of the third variety of tea be x Rs./kg.
The total mixture is worth Rs. 153/kg. Since the ratio of the tea varieties is 1:1:2, we can assume the quantities of each type of tea in the mixture to be:
The total cost of the mixture can be expressed as the weighted average cost of the individual varieties based on their respective quantities.
Let's compute the cost per unit for the mixture:
The total quantity of the mixture is:
The average price per kg of the mixture is given as Rs. 153. Therefore, we set up the equation:
First, simplify the numerator:
Next, substitute this back into the equation and solve for x:
Multiply both sides by 4 to clear the denominator:
Now, isolate x:
Thus, the price of the third variety of tea is Rs. 175.50 per kg.
Suppose the vessel initially contains 8 litres of liquid.
Let x litres of this liquid be replaced with water.
Quantity of water in new mixture =
litres.
Quantity of syrup in new mixture = litres.
=> 5x + 24 = 40 - 5x
=> 10x = 16 => x = 8/5
So, part of the mixture replaced = = 1/5.
Therefore x = 21%
Number of liters of water in 125 liters of the mixture = 20% of 150 = 1/5 of 150 = 30 liters
Let us Assume that another 'P' liters of water are added to the mixture to make water 25% of the new mixture. So, the total amount of water becomes (30 + P) and the total volume of the mixture becomes (150 + P)
Thus, (30 + P) = 25% of (150 + P)
Solving, we get P = 10 liters
By the rule of alligation:
C.P. of 1 kg sugar of 1st kind C.P. of 1 kg sugar of 2nd kind
Therefore, Ratio of quantities of 1st and 2nd kind = 14 : 6 = 7 : 3.
Let x kg of sugar of 1st kind be mixed with 27 kg of 2nd kind.
Then, 7 : 3 = x : 27 or x = (7 x 27 / 3) = 63 kg.
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