To solve the problem, let's define the prices and quantities of the different varieties of tea being mixed.
Given:
Let the price of the third variety of tea be x Rs./kg.
The total mixture is worth Rs. 153/kg. Since the ratio of the tea varieties is 1:1:2, we can assume the quantities of each type of tea in the mixture to be:
The total cost of the mixture can be expressed as the weighted average cost of the individual varieties based on their respective quantities.
Let's compute the cost per unit for the mixture:
The total quantity of the mixture is:
The average price per kg of the mixture is given as Rs. 153. Therefore, we set up the equation:
First, simplify the numerator:
Next, substitute this back into the equation and solve for x:
Multiply both sides by 4 to clear the denominator:
Now, isolate x:
Thus, the price of the third variety of tea is Rs. 175.50 per kg.
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
NA
Each previous number is multiplied by 2.
? 8 m shadow means original height = 12 m
? 1 m shadow means original height = 12/8 m
? 100 m shadow means original height = (12/8) x 100 m
= (6/4) x 100 = 6 x 25 = 150 m
Let 8% of 96 = y of 1/25
? (8 x 96)/100 = y/25
? y = (8 x 96 x 25)/100 = 192
Since the principal is not given, so data is inadequate.
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