A Person X started at 3 hours earlier at 40km/h from a place P, then another person Y followed him at 60km/h. Started his journey at 3 O'clock, afternoon. What is the diference in time when X was30 km ahead of Y and when Y was 30 km ahead of X?

? a / b = 2/3 and 2 / a = 1/2
? a/b x 2/a = 2/3 x 1/2
? 2/b = 1/3
? b = 6

0.6 x a = 0.09 x b
? a/b = 0.09 / 0.06 = 9 / 60 = 3 / 20 = 3 : 20

Let a/3 = b/8 = K
Then, a = 3K, b = 8K
? (a + 3) / (b + 8) = (3K + 3) / (8K + 8)
= [3( K + 1)] / [8(K+1)] = 3/8
? ( a + 3 ) : (b + 8) = 3 : 8

Series pattern +15, + 30, +60, +120
? Missing term = 49 + 60 = 109

777777 / 11 = 70707.

NA

According to the question,
1728 = 1331(1 + R/100)³
1728/1331 = (1 + R/100)³
? (12/11)³ = (1 + R/100)³
? 1 + R/100 = 12/11
? R/100 = (12/11) - 1 = 1/11
? R = 100/11= 9.09%

Here, M + N = 10 and MN = 20
According to the question,
(1/M) + (1/N) = (M + N) / MN = 10/20 = 1/2

Time = distance / speed
=110 / {60 x 18/5} = 6.6 sec.