a+b=5 ...(1) and 3a+2b=20 ...(2)
Multiplying (1) by 2 and subtracting from (2), we get : a=10.
Putting a=10 in (1), we get : b=-5
Therefore, (3a+b) = 3 x 10+(-5)=30-5=25.
The given equation is in Mixed fraction.
Now to solve this type of fractions,
=>
=> ? =
=> ? = 19.07
Let ? = p
38 x 7500/100 + p x 375/100 = 50 x 6000/100
=> 38 x 75 + 3.75p = 3000
=> 3.75p = 3000 - 2850
=> p = 150/3.75
=> p = ? = 40
Let the Oranges be 'O', Bananas be 'B' and Apples be 'A'
From the given data,
2O + 3B + 4A = 15 ...... (I)
3O + 2B + A = 10 ..... (II)
On adding (I) and (II),
5O + 5B + 5A = 25
O + B + A = 5
4O + 4B + 4A = 20.
Given that ,
=> x-y=3, x+y=5
=> x = 4
Let, Hema attempted 'k' sum correctly, then
k x 3 -2 x(35-k) = 60
5k = 130
k = 26
so 26 correct sums.
=
It is in the form of
= 2(40000 + 289) = 80578.
Let the price of each note book be Rs.x.
Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y.
Hence xy = 300
=> y = 300/x
(x + 5)(y - 10) = 300 => xy + 5y - 10x - 50 = xy
=>5(300/x) - 10x - 50 = 0 =>
multiplying both sides by -1/10x
=>
=> x(x + 15) - 10(x + 15) = 0
=> x = 10 or -15
As x>0, x = 10.
The given 3b - 7 < 32 can be solved as
3b - 7 < 32
3b < 39
b < 13.
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