Let the number of buffaoes be x and number of ducks be y.
Then 4x + 2y = 2(x + y) + 24
=> 2x = 24
=> x = 12.
= 70,000.
Given
Using unit digit method,
On LHS,
1 x 1 x 1 = 1
sqrt of last digit 1 => it must end with either 9 or 1
so now
1 x 1 = 1
1 x 9 = 9
On RHS,
? + 89
=> ? = ...1 - 89 = last digit is 11- 9 = 2
or
=> ? = ...9 - 89 = last digit is 9 - 9 = 0
Here in the options last digit 2 is option C.
Let the score be x. Then the highest score = 3x/11.
Reminder = (x - 3x/11) = 8x/11 .Next the highest score = 3/11 of 8x/11 = 24x/121.
3x/11 - 24x/11 = 9 <=> 33x - 24x = 9*121 <=> x= 121..
Apply
Hence the answer is 1.5 + 4.7 + 3.8 = 10.
Let the number of 20 paise coins be x. Then the no of 25 paise coins = (324 - x).
0.20 * (x) + 0.25 (324 - x) = 71 => x = 200..
3/5 of 350 - 4/7 of 210 = 210 - 120 = 90.
Let the Oranges be 'O', Bananas be 'B' and Apples be 'A'
From the given data,
2O + 3B + 4A = 15 ...... (I)
3O + 2B + A = 10 ..... (II)
On adding (I) and (II),
5O + 5B + 5A = 25
O + B + A = 5
4O + 4B + 4A = 20.
Let ? = p
38 x 7500/100 + p x 375/100 = 50 x 6000/100
=> 38 x 75 + 3.75p = 3000
=> 3.75p = 3000 - 2850
=> p = 150/3.75
=> p = ? = 40
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