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- Question
The highest score in an inning was 3/11 of the total and the next highest was 3/11 of the reminder . If the score differ by 9, the total score was :
Options- A. 110
- B. 121
- C. 132
- D. 143
- Correct Answer
- 121
ExplanationLet the score be x. Then the highest score = 3x/11.
Reminder = (x - 3x/11) = 8x/11 .Next the highest score = 3/11 of 8x/11 = 24x/121.
3x/11 - 24x/11 = 9 <=> 33x - 24x = 9*121 <=> x= 121..
- 1. If carton containing a dozen mirrors is dropped, which of the following cannot be the ratio of broken mirrors to unbroken mirrors?
Options- A. 2 : 1
- B. 3 : 1
- C. 3 : 2
- D. 7 : 5 Discuss
- 2. Find the missing number in the given number series? 514, 470, ?, 415, 404
Options- A. 441
- B. 437
- C. 426
- D. 420 Discuss
- 3. The third propotional to 0.8 and 0.2 is?
Options- A. 0.4
- B. 0.8
- C. 0.05
- D. 0.032 Discuss
- 4. Find the Odd One Out? 3, 4, 14, 48, 576, 27648
Options- A. 4
- B. 14
- C. 48
- D. 27648 Discuss
- 5. Find the odd one out? 6, 3, 3, 4.5, 10
Options- A. 3
- B. 4.5
- C. 6
- D. 10 Discuss
- 6. What number should be added to each one of 6, 14, 18 and 38 to make them equally proportionate?
Options- A. 1
- B. 2
- C. 3
- D. 4 Discuss
- 7. A and B invest in a business in the ratio 3 : 2. If 5% of the total profit goes to charity and A's share is Rs. 855, the total profit is :
Options- A. 500
- B. 1000
- C. 1500
- D. 2000 Discuss
- 8. A, B, C started a business with their investments in the ratio 1:3 :5. After 4 months, A invested the same amount as before and B as well as C withdrew half of their investments. The ratio of their profits at the end of the year is :
Options- A. 1 : 2 : 3
- B. 3 : 4 : 15
- C. 3 : 5 : 10
- D. 5 : 6 : 10 Discuss
- 9. A and B are partners in a business. A contributes 1/4 of the capital for 15 months and B received 2/3 of the profit. For how long B's money was used ?
Options- A. 3 months
- B. 6 months
- C. 10 months
- D. 12 months Discuss
- 10. If 2A = 3B = 4C , then A : B : C is?
Options- A. 2 : 3 : 4
- B. 4 : 3 : 2
- C. 6 : 4 : 3
- D. 3 : 4 : 6 Discuss
More questions
Correct Answer: 3 : 2
Explanation:
For dividing 12 into two whole numbers, the sum of the terms of the ratio must be a factor of 12. so, they cannot be in the ratio 3 :2.
Correct Answer: 437
Explanation:
Given number series is 514 470 ? 415 404
Here the pattern it follows is
514
514 - 44 = 470
470 - 33 = 437
437 - 22 = 415
415 - 11 = 404
Hence, the missing number in the given number series is 437.
Correct Answer: 0.05
Explanation:
Let 0.8 : 0.2 : : 0.2 : N
Then 0.8 x N = 0.2 x 0.2
? N = ( 0.2 x 0.2) / 0.8 = 0.04 / 0.08 = 4/80 = 0.05
Correct Answer: 14
Explanation:
Given Number series is :
3 4 14 48 576 27648
It follows a pattern that,
3
4
4 x 3 = 12 but not 14
12 x 4 = 48
48 x 12 = 576
576 x 48 = 27648
Hence, the odd one in the given Number Series is 14.
Correct Answer: 10
Explanation:
Here the given number series is 6, 3, 3, 4.5, 10
The odd one in the given series is 10
The pattern it follows is
6
6 x 0.5 = 3
3 x 1 = 3
3 x 1.5 = 4.5
4.5 x 2 = 9
Hence, the odd number is 10.
Correct Answer: 2
Explanation:
Let the number be N,
From question, (6 + N) / (14 + N) = (18 + N) / (38 + N)
? (6 + N) x (38 + N ) = (18 + N ) x (14 + N )
? N2 + 44N + 228 = N2 + 32N + 252
? 12N = 24
? N = 2
Correct Answer: 1500
Explanation:
Let the total profit be Rs. 100.
After paying to charity, A's share = (95*3/5) = Rs. 57.
If A's share is Rs. 57, total profit = Rs. 100.
If A's share is Rs. 855, total profit = (100/57*855) = 1500.
Correct Answer: 5 : 6 : 10
Explanation:
Let their initial investments be x, 3x and 5x respectively. Then,
A:B:C = (x*4+2x*8) : (3x*4+(3x/2)*8) : (5x*4+(5x/2)*8)
20x : 24x : 40x = 5 : 6 : 10
Correct Answer: 10 months
Explanation:
Let the total profit be Rs. z. Then,
B's share = Rs. 2z/3, A's share = Rs. ( z - 2z/3 ) = Rs. z/3.
A : B = z/3 : 2z/3 = 1:2
Let the total capital be Rs, X and suppose B's money was used for x months. Then.
(1(x) / 4 * 15) / (3x) / 4 * y) = 1/2 <=> y = (15 * 2 / 3) = 10 .
Thus, B's money was used for 10 months.
Correct Answer: 6 : 4 : 3
Explanation:
Let 2A = 3B = 4C = x
Then A = x/2, B = x/3 and C = x/4
? A : B : C = x/2 : x/3 : x/4
Hence A : B : C = 6 : 4 : 3
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