16 : 56 :: 32 : ?
Let the required number be 'n'
The given numbers follow a logic that,
16/56 = 2/7
=> 32/n = 2/7
=> 32 x 7/2 = n
=> n = 112.
Hence, 16 : 56 :: 32 : 112.
If the person who gets 1/4 of the whole gets thrice of what the others get on an average, each one will get =1/3×1/4=112 of the whole.
Therefore, if there are k persons other than the person who gets one-fourth, then 1/4 + k/12 = 1
? k=9
Hence, total number of people = 10.
Let the number of failed students be x
=> Number of passed students = 4x
So total number of students was 5x
From the given data,
If total number of students be 5x ? 35
=> 4x-35-9/x+9 = 2/1
=> 4x ? 44 = 2(x + 9)
=> 4x ? 2x = 18 + 44
=> x = 31
Total number = 31×5
= 155
Let the incomes of A and B be 3P and 4P.
If each saves Rs. 100 per month, then their expenditures = Income - savings = (3P - 100) and (4P - 100).
The ratio of their expenditures is given as 1 : 2.
Therefor, (3P - 100) : (4P - 100) = 1 : 2
Solving, We get P = 50. Substitute this value of P in 3P and 4P.
Thus, their incomes are : Rs.150 and Rs.200
Given total rupees = 20 Rs
No. of one rupee stamps = 3
Now, remaining money = Rs. 17
With that he buys only 2 and 5 rupee stamps
Let number of Rs. 5 stamps = K
Let number of Rs. 2 stamps = L
5K + 2L = 17
K = 3, L = 1 (possible)
L = 6, K = 1 (possible)
=> But given that they are different in number so, K is not equal to 3
one rupee stamps = 3
2 two stamps = 6
5 rupee stamps = 1
Total number of stamps = 10.
Let the two numbers be x and y
Given x : y = 3 : 7 .....(1)
Now, x+6 : y+6 = 5 : 9 .....(2)
From (1), x = 3y/7
From (2), 5y - 9x = 24
=> 5y - 9(3y/7) = 24
=> y = 21
=> From(1), x = 9
Hence, the two numbers be 9 and 21
Let Pencils = 10x, Pens = 2x & Exercise books = 3x. Now, 10x = 120 hence x = 12.
Number of exercise books = 3x = 36.
From the given data,
Virat : Rohit = 3 : 2
Rohit : Dhoni = 3 : 2
Ratio of runs scored by Virat, Rohit and Dhoni respectively
= 3 x 3 : 2 x 3 : 2 x 2
9 : 6 : 4
Runs scored by Virat = 9/19 x 285 = 135.
Total student= 39, boys : girls = 2:1, hence no of boys= 2/3(39)= 26
num of girls= 1/3(39) = 13 , since radhika ranked 15 among 39 student from top
and ranked 8 among girls from bottom , this means 7 girls are below radhika, rest 13-9= 5 girls are above her, now from 14 toper 5 are girls hence 14-5=9 boys.
Hence num of boys below radhika are 26-9=17
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