A : B = 100 : 90.
A : C = 100 : 72.
B:C = B/A*A/C = 90/100*100/72 = 90/72
When B runs 90 m, C runs 72 m.
When B runs 100 m, C runs (72/90*100)m = 80m
B can give C 20 m.
4th observation i.e., 8 is the median.
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
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