Loss%= (common gain or loss % / 10)2 = (10/10)² % = 1%.
Total investment = Rs. (120 * 80 + 280 + (40/100) * 120 + 72).
= Rs. (9600 + 280+48 + 72) = Rs, 10000.
Sell price of 120 reams = 108% of Rs. 10000 = Rs. 10800.
Sell Price per ream = Rs. [10800/120] = Rs. 90.
when the water is freely available and all the water is sold at the price of the milk, then the water gives the profit on the cost of 20 liters of milk.
Therefore, profit percentage = (5/20) x 100 =25 % [ Profit %= (Profit/C.P)*100]
110% of S.P. = Rs. 616
S.P. = (616 x 100)/110 = Rs. 560
C.P = (110 x 560)/112 = Rs. 500
Cost Price of 5 kg = Rs.(14*2 + x*3) = (28 + 3x).
Sell price of 5 kg = Rs. (22x5) = Rs. 110.
[{110 - (28 + 3x)}/(28 + 3x) ]* 100 =10
[82-3x/28 + 3x]= 1 / 10
820 - 30x = 28 +3x
33x = 792
x = 24
33.33% profit means there is one part water and 3 part is pure wine. so the required ratio of water and wine in the mixture is 1:3
Given M.P=45,S.P=42, Profit = 0.05
Let C.P=x , Then
Profit = (42-x)/x = 0.05
=> x = 40.
CP = 100, SP (with tax) =120
New SP = 100 - 5 = 95
Effective discount = 120 - 95 = 25
So, at SP of 95 ----> discount = 25
and at SP of 3325 -----> discount =
cost price = (225 + 15) = 240 sell price = 300
gain = (60/240)*100 = 25%
When the water is freely available and all the water is sold at the price of the milk, then the water gives the profit on the cost of 20 litres of milk.
Since, the profit % =
Therefore, profit percentage = = 25%
Let C.P. = Rs. C.
Then, 832 - C = C - 448
2C = 1280 => C = 640
Required S.P. = 150% of Rs. 640 = 150/100 x 640 = Rs. 960.
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