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- Question
How much time will a train of length 200 m moving at a speed of 72 kmph take to cross another train of length 300 m, moving at 36 kmph in the same direction ?
Options- A. 58 sec
- B. 62 sec
- C. 60 sec
- D. 50 sec
- Correct Answer
- 50 sec
ExplanationThe distance to be covered = Sum of their lengths = 200 + 300 = 500 m.
Relative speed = 72 -36 = 36 kmph = 36 x 5/18 = 10 mps.
Time required = d/s = 500/10 = 50 sec.
- 1. A train for Fathehpur leaves for every 2 hrs 30 min from Agra station. An announcement was made that train left 37 mins ago and next train comes at 17:00hrs. At what time was the announcement made ?
Options- A. 15:07 hrs
- B. 15:20 hrs
- C. 15:05 hrs
- D. 15:00 hrs Discuss
- 2. An express train takes 4 seconds to enter tunnel which is 1 km long. If it is traveling at 108 km an hour, how long will it take to pass completely through the tunnel ?
Options- A. 33 sec
- B. 37.33 sec
- C. 36.43 sec
- D. 32 sec Discuss
- 3. A 150 m long train crosses another 210 m long train running in the opposite direction in 10.8 seconds. If the shorter train crosses a pole in 12 seconds, what is the speed of longer train ?
Options- A. 75 kmph
- B. 80 kmph
- C. 54 kmph
- D. 45 kmph Discuss
- 4. A passenger train is moving at a speed of 120 km/hr. If the length of the train is 101 meters, how long will it take to cross a railway platform 154 meters long ?
Options- A. 6.24 sec
- B. 6.58 sec
- C. 7.325 sec
- D. 7.65 sec Discuss
- 5. A train 125 m long passes a man, running at 4 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Options- A. 49 kmph
- B. 50 kmph
- C. 51 kmph
- D. 52 kmph Discuss
- 6. A train 900 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is ?
Options- A. 400 m
- B. 300 m
- C. 500 m
- D. 600 m Discuss
- 7. A train covered k km at 40 kmph and another 2k km at 20 kmph. Find the average speed of the train in covering the entire 3k km ?
Options- A. 28 kmph
- B. 24 kmph
- C. 26 kmph
- D. 32 kmph Discuss
- 8. Two trains, one from Hyderabd to Bangalore and the other from Bangalore to Hyderabad, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is ?
Options- A. 3 : 4
- B. 4 : 3
- C. 2 : 3
- D. 3 : 2 Discuss
- 9. The length of a brigade which a train 130 m long and traveling at 45kmph can cross in 30 seconds, is
Options- A. 196 mts
- B. 220 mts
- C. 230 mts
- D. 245 mts Discuss
- 10. Train X crosses a stationary train Y in 60 seconds and a pole in 25 seconds with the same speed. The length of the train X is 300 m. What is the length of the stationary train Y ?
Options- A. 360 m
- B. 420 m
- C. 460 m
- D. 320 m Discuss
Problems on Trains
Search Results
Correct Answer: 15:07 hrs
Explanation:
Next train comes at 17:00 hrs.
So, last train will be = 17:00hrs - 2:30hrs
= 14:30hrs
Announcement made after 37 min of the last train.
S0, 14:30hrs + 00:37 min
= 15:07 hrs.
Correct Answer: 37.33 sec
Explanation:
Speed = 108 km/hr
enter a tunnel,, means that the train covers a distance equal to its own length
so (108 x 5/18) = x/4 where x= length of train
hence x = 120 mtrs
to pass completely train has to travel a distance = (x + tunnel length) that is 1120 mtrs.
so (1120/t) = (108x5/18)
t = 37.33 sec
Correct Answer: 75 kmph
Explanation:
Total distance = 150 + 210 = 360 mts
Time taken to cross each other when moving in opposite direction = 10.8 sec
Relative speed of trains = (350/10.8) x 18/5 = 3600/30 = 120 kmph
Speed of shorter train = (150/12) x 18/5 = 45 kmph
Hence, speed of longer train = 120 - 45 = 75 kmph.
Correct Answer: 7.65 sec
Explanation:
Here total distance = 154 + 101 = 255 mts
Given speed = 120 kmph = 120x5/18 m/sec
Hence, Time = d/s = 255x18/120x5 = 7.65 sec
Correct Answer: 49 kmph
Explanation:
Speed of the train relative to man
= (125/10) m/sec = (25/2) m/sec.
[(25/2) x (18/5)] km/hr = 45 km/hr.
Let the speed of the train be 'x' km/hr.
Then, relative speed = (x - 4) km/hr.
x - 4 = 45 => x = 49 km/hr.
Correct Answer: 400 m
Explanation:
Speed = 78 x 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (900 + x)/60 = 65/3
x = 400 m.
Correct Answer: 24 kmph
Explanation:
Total time taken = k/40 + 2k/20 hours
= 5k/40 = k/8 hours
Average speed = 3k/(k/8) = 24 kmph.
Correct Answer: 4 : 3
Explanation:
Let us name the trains as A and B.
Then, (A's speed) : (B's speed)
= ?b : ?a = ?16 : ?9 = 4:3
Correct Answer: 245 mts
Explanation:
Let the length of the brigade is x mts
Then Distance = 130 + x mts
given speed = 45 kmph = 45 x5/18 m/s
Time = 30 sec
T = D/S
=> 30 = 130+x/(45x5/18)
=> x = 245 mts.
Correct Answer: 420 m
Explanation:
Let the length of the stationary train Y be LY
Given that length of train X, LX = 300 m
Let the speed of Train X be V.
Since the train X crosses train Y and a pole in 60 seconds and 25 seconds respectively.
=> 300/V = 25 ---> ( 1 )
(300 + LY) / V = 60 ---> ( 2 )
From (1) V = 300/25 = 12 m/sec.
From (2) (300 + LY)/12 = 60
=> 300 + LY = 60 (12) = 720
=> LY = 720 - 300 = 420 m
Length of the stationary train = 420 m
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