Let Ishika and her daughter present ages be p and q
From the given data,
p = 4/3(p - 9)
=> p = 36 years
Hence, Ishika's present age = 36 years and
Her daughter's present age = 1/6 x 36 = 6 years
Now, required her daughter?s age three years ago = 6 - 3 = 3 years.
Given the average age of couple and their son = 40
=> Sum of age (H +W +S) = 40×3
Let the age of daughter in law at the time of marriage = D years
Now after 10 years,
(H + S +W) + 3×12 + D +12 + 10 = 38×5
178 + D = 190
D = 190 -178 = 12 years
Let Shilpa's present age is p years
According to question,
p = 4(x+4) ? 4(x?4)
p = 4x+16 ? 4x+16
p = 32
Shilpa's present age = 32 years
Rajeev is four years older than Shilpa
=> Shilpa's present age = Rajeev's age 4 years before.
=> Rajeev's age 4 years before = 32 years.
Let varun's age = x yrs.
From the given conditions,
x+1 = 2(x-12)
x = 25 years.
Let the present ages of A and B be 'x' and 'y' respectively
From the given data,
[(x-2) + (y-2)]/2 = 26
=> x+y = 56
But given the age of A, 5 years hence is 40 yrs => present age of A = 40 - 5 = 35 yrs
=> x = 35 => y = 56 - 35 = 21
=> Age of B = 21 yrs
Given B is 5 years younger to C,
=> Age of C = 21 + 5 = 26 yrs
=> Required Difference between ages of A and C = 35 - 26 = 9 yrs.
Let the present age of Deepa = 5p
Let the present age of Hyma = 6p
After four years their ratio = 6 : 7
=>
=> 35p + 28 = 36p + 24
=> p = 4
Therefore, the difference between their ages = 24 - 20 = 4 years.
Let number of boys = x , Let number of girls = y
Total numbers of students = x + y
(x + y) × 15.8 = 16.4x + 15.4y
0.6x = 0.4y
x/y = 0.4/0.6 = 2/3
Ratio of boys and girls in the class is 2:3
Let Anushka age = X
Charu latha 12 yrs older than Anushka so Charu latha age = x+12
Kajal is thrice as old as Anushka so Kajal age = 3x
The ages of Anushka, Kajal and Charu latha together are 57 years
i.e x + (x+12) + 3x = 57
=> 5x = 45
:- x = 9
Anushka age = 9
Kajal age = 3x = 27
Charu latha age = x+12 = 21
Let the age of the daughter today be ?x? years.
Mother?s age today = 3x years
After 10 years, we have
3x + 10 = 2(x + 10)
x = 10 years.
Raj Tarun's age = 0 when he was born.
Then, given his brother is 6 years old.
Then his father is 6 + 32 = 38 when Raj Tarun was born
And his mother is 3 years yonger than his father => so his mother was 35 years old when Raj Tarun was born
and his sister is 25 year younger than his mother
so Raj Tarun's sister was 10 years old when Raj Tarun was born.
Let the mother's present age be x years.
Then, the person's present age = 2/5 x years.
(2x/5 + 8) = 1/2 (x + 8)
2(2x + 40) = 5(x + 8) => x = 40.
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