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- Question
The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years.
Options- A. 60 years
- B. 65 years
- C. 70 years
- D. 75 years
- Correct Answer
- 70 years
Explanation
Take A's age as a, B's age as b. a + b = 60 a = 2b So, b + 2b = 60 3b = 60 b = 20 a = 40 So A is 40, B is 20. In 5 years' time, A will be 45, B will be 25. so the sum of their ages will be 70 - 1. Sachin is younger than Rahul by 7 years. If the ratio of their ages is 7:9, find the age of Sachin
Options- A. 24.5
- B. 25.5
- C. 26.5
- D. 27.5 Discuss
- 2. The ratio of the father's age to the son's age is 3: 1. The product of their ages is 147. The ratio of their ages after 5 years will be?
Options- A. 6:13
- B. 15:6
- C. 6:15
- D. 13:6 Discuss
- 3. Six years ago Anita was P times as old as Ben was. If Anita is now 17 years old, how old is Ben now in terms of P ?
Options- A. 11/P + 6
- B. P/11 +6
- C. 17 - P/6
- D. 17/P Discuss
- 4. "I am five times as old as you were, when I was as old as you are", said a man to his son. Find out their present ages, if the sum of their ages is 64 years ?
Options- A. Father = 50; Son =14
- B. Father = 40; Son =24
- C. Father = 60; Son =4
- D. Father = 48; Son =16 Discuss
- 5. The average age of a group of 10 students is 15 years. When 5 more students join the group, the average age increase by 1 year. The average age of the new students is?
Options- A. 18 years
- B. 21 years
- C. 19 years
- D. 20 years Discuss
- 6. When I was married 10 years ago my wife is the 6th member of the family. Today my father died and a baby born to me.The average age of my family during my marriage is same as today. What is the age of Father when he died ?
Options- A. 50 yrs
- B. 60 yrs
- C. 70 yrs
- D. 65 yrs Discuss
- 7. Sivagami is 2 years elder than Meena. After 6 years the total of their ages will be 7 times of their current age. Then age of Sivagami is :
Options- A. 19 years
- B. 17 years
- C. 15 years
- D. data inadequate Discuss
- 8. If two times of the daughter?s age in years is included to the mother?s age, the total is 70 and if two times of the mother?s age is included to the daughter?s age, the total is 95. So the Mother?s age is,
Options- A. 30
- B. 38
- C. 40
- D. 41 Discuss
- 9. The sum of the ages of 5 children born at the intervals of 3 years each is 50 years. what is the age of the youngest child ?
Options- A. 4
- B. 8
- C. 10
- D. None Discuss
- 10. A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is
Options- A. 20
- B. 21
- C. 22
- D. 23 Discuss
Problems on Ages
Search Results
Correct Answer: 24.5
Correct Answer: 13:6
Explanation:
Let the son's age = x. therefore, the father's age be 3x, Given the product of their ages = 147. => x * 3x = 147 => 3x² = 147. => x² = (147/3) => x² = 49 => x = 7. Therefore, present age of son = x = 7 years. Present age of father = 3x = 21. Age of father after 5 years = 21+5 = 26 years. Age of son after 5 years = 7+5 = 12 years. Ratio=13 : 6
Correct Answer: 11/P + 6
Explanation:
Let Ben?s age now be B
Anita?s age now is A.
(A - 6) = P(B - 6)
But A is 17 and therefore 11 = P(B - 6)
11/P = B-6
(11/P) + 6 = B
Correct Answer: Father = 40; Son =24
Explanation:
Let the present age of the man be 'P' and son be 'Q',
Given, P + Q = 64 or Q = (64 - P)
Now the man says "I am five times as old as you were, when I was as old as you are",
So, P = 5[B - (P - Q)]
We get 6P = 10Q,
Substitute value for Q,
6P = 10(64 - P),
Therefore P = 40, Q = 24.
Correct Answer: 18 years
Explanation:
Total age of 10 students = 150 years Total age of 15 students = 240 years Total age of 5 new students = 240 - 150 = 90 years Therefore, average age of 5 new students = 90/5 = 18 years
Correct Answer: 60 yrs
Explanation:
Let the Father be x years when he died
Average Age 10 years ago be A
Total Age 10 years ago = 6*A
Total Age after 10 years(Just before father's Death) = 6A + 6*10 = 6A + 60
Father Died and Baby was born => the Total number of people in the family is Same (6)
Baby born today so age of baby = 0
(6A +60 - x)/6 = 6A/6
=> A + 10 -(x/6) = A
=> x/6 = 10
=> x = 60
Therefore we can conclude that the father was 60 years old when he died.
Correct Answer: data inadequate
Explanation:
Let Meena?s age = A.
Then Sivagami?s age = A + 2
After 6 years the total of their ages will be 7 times of what?
Not clear.
So the given data are inadequate.
Correct Answer: 40
Explanation:
Let daughter?s age = A and mother?s age = B
Given: 2A+B = 70 and A+2B = 95
Solving B, we will get B = 40.
Correct Answer: 4
Explanation:
Let x = the youngest child. Each of the other four children will then be x+3, x+6, x+9, x+12.
We know that the sum of their ages is 50 .
so, x+(x+3)+(x+6)+(x+9)+(x+12) = 50
=> x= 4
The youngest child is 4 years old.
Correct Answer: 22
Explanation:
Let the son's present age be x years. Then, man's present age = (x + 24) years
=> (x + 24) + 2 = 2(x + 2)
=> x + 26 = 2x + 4
So, x = 22
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